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Anon25 [30]
2 years ago
10

How do you find the area of a triangle when given only the lengths of three sides?

Mathematics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

Use Heron's formula; see below.

Step-by-step explanation:

Use Heron's formula.

Let the sides of the triangle have lengths a, b, and c.

s = \dfrac{a + b + c}{2}

area = \sqrt{s(s - a)(s - b)(s - c)}

Example:

A triangle has side lengths 3, 4, and 5 units.

Find the area of the triangle.

s = \dfrac{a + b + c}{2}

s = \dfrac{3 + 4 + 5}{2}

s = 6

area = \sqrt{s(s - a)(s - b)(s - c)}

area = \sqrt{6(6 - 3)(6 - 4)(6 - 5)}

area = \sqrt{6(3)(2)(1)}

area = \sqrt{36}

area = 6

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(x 4 - 3x 3 + 3x 2 - 3x + 6) (x - 2)
Vlada [557]

Answer:

x^5 - 5 x^4 + 9 x^3 - 9 x^2 + 12 x - 12

Step-by-step explanation:

(x ^4 - 3x^3 + 3x^2 - 3x + 6) (x - 2)

Distribute the x to all the terms in the first parentheses

(x^ 4  *x - 3x^ 3  *x + 3x^ 2   *x - 3x   *x + 6*x)

Then simplify

(x^5 - 3x^4 + 3x^ 3 - 3x2 + 6x)

Distribute the -2 to all the terms in the first parentheses

(x^ 4  *(-2) - 3x^ 3  *(-2) + 3x^ 2   *(-2) - 3x   *(-2) + 6*(-2))

Then simplify

(-2x^4 +6x^3 -6x^ 2 +6x -12)

Add the terms together

(x^5 - 3x^4 + 3x^ 3 - 3x2 + 6x) +(-2x^4 +6x^3 -6x^ 2 +6x -12)

x^5 - 5 x^4 + 9 x^3 - 9 x^2 + 12 x - 12

4 0
3 years ago
Could someone help me giving brainliest
VARVARA [1.3K]

Answer:

The first one. Top left.

Step-by-step explanation:

The top right one makes a triangular prism.

I don't even know if the bottom right is even a thing.

The bottom left is a cube.

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Answer:

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Step-by-step explanation:

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3 years ago
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Determine whether or not 630 is a triangular number. start with the formula t n = n ( n + 1 ) 2 and then use the quadratic formu
ziro4ka [17]
Triangular sequence = n(n + 1)/2

If 630 is a triangular number, then:

n(n + 1)/2  = 630

Then n should be a positive whole number if 630 is a triangular number.

n(n + 1)/2  = 630

n(n + 1)  = 2*630

n(n + 1)  = 1260

n² + n = 1260

n² + n - 1260 = 0

By trial an error note that 1260 = 35 * 36

n² + n - 1260 = 0

Replace n with 36n - 35n

n² + 36n - 35n - 1260 = 0

n(n + 36) - 35(n + 36) = 0

(n + 36)(n - 35) = 0

n + 36 = 0   or   n - 35 = 0

n = 0 - 36,   or  n = 0 + 35

n = -36, or 35

n can not be negative. 

n = 35 is valid.

Since n is a positive whole number, that means 630 is a triangular number.

So the answer is True.
7 0
3 years ago
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