
<em><u>Solution:</u></em>
Given that we have to find the sum of 
<em><u>Let us first convert the mixed fractions to improper fractions</u></em>
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator
Therefore,

Now we can add both the fractions

Make the denominators same

Now convert the fraction to mixed number
When we divide 53 by 10 , the remainder is 3
Therefore, write 5 as a whole number and and 3 as numerator and 10 as denominator

Thus the sum of given mixed fraction is 
(7-1)/3=x
(14-2)/4=x
1. x=2
2. x=3
If you are looking for the number of bananas per bag you must first subtract your remainders from the total number of bananas, then divide those bananas by the number of bags and you have your answer.
3.5, it is the coefficient and describes how many n there are
Mary Purchase shares = $80,000
Mary Sells shares = $55,000
Loss she can claim for = $80,000 - $55,000
= $ 25,000