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3 years ago

So, sunny is 16 he is 132 pounds

Mathematics

1 answer:

Amanda [17]3 years ago

6 0

The answer would be 79 because the dog punched the alpaca

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Which equation shows how you can find the number of minutes in one year

tiny-mole [99]

Minutes x every minute of the day
I think

7 0

3 years ago

Read 2 more answers

The last part is function but need help asap

quester [9]

It would be the top one

4 0

3 years ago

(1 point) For the function f graphed below, find the following limits:

dedylja [7]

The limits to the given function are as follows:

1. ∞

2. -∞

3. ∞

4. 1

5. -∞

<h3>What is a limit?</h3>

A limit is given by the <u>value of function f(x) as x tends to a value</u>.

For this problem, at x = 0, we have that to the left the function goes to positive infinity, while to the right it goes to negative infinity, hence:

1. lim f(x) = ∞

x->0-

2. lim f(x) = -∞

x->0+

At x = 2, the function goes to infinity to the left and to the right, hence:

3. lim f(x) = ∞

x->2

To the left of the graph, the function goes to negative infinity, while to the right it goes to 1, hence:

4. lim f(x) = 1

x-> ∞

5. lim f(x) = -∞

x-> -∞

More can be learned about limits of functions at brainly.com/question/26270080

#SPJ1

7 0

2 years ago

If f(x) = 3x2 − 8x, 0 ≤ x ≤ 3, evaluate the Riemann sum with n = 6, taking the sample points to be right endpoints.

denis23 [38]

Split up the interval [0, 3] into 6 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

The right endpoints are given by the arithmetic sequence,

$r_i=0+\dfrac i2=\dfrac i2$

with $1\le i\le6$ .

We approximate the integral of $f(x)$ on the interval [0, 3] by the Riemann sum,

$\displaystyle\int_0^3f(x)\,\mathrm dx=\sum_{i=1}^6f(r_i)\Delta x_i$

$\displaystyle=\frac{3-0}6\sum_{i=1}^6\left(3{r_i}^2-8r_i\right)$

$\displaystyle=\frac12\sum_{i=1}^6\left(\frac{3i^2}4-4i\right)$

$\displaystyle=\frac38\sum_{i=1}^6i^2-2\sum_{i=1}^6i$

Recall the formulas,

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$

Then the value of the integral is approximately

$\displaystyle=\frac38\cdot\frac{6\cdot7\cdot13}6-2\cdot\frac{6\cdot7}2=\boxed{-\frac{63}8}=-7.875$

Compare to the exact value of the integral, -9.

7 0

3 years ago

The midpoint of ab is M (-6,1 ). if the coordinates of A are (-7,-3 ),what are the coordinates of B

Scrat [10]

Answer:

B(-5,5).

Step-by-step explanation:

It is given that midpoint of AB is M (-6,1).

Coordinates of A are (-7,-3 ).

We need to find the coordinates of point B.

Let coordinates of point B are (a,b).

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Midpoint of AB is

$Midpoint=\left(\dfrac{-7+a}{2},\dfrac{-3+b}{2}\right)$

$(-6,1)=\left(\dfrac{-7+a}{2},\dfrac{-3+b}{2}\right)$

On comparing both sides, we get

$\dfrac{-7+a}{2}=-6$

$-7+a=-12$

$a=-12+7$

$a=-5$

$\dfrac{-3+b}{2}=1$

$-3+b=2$

$b=2+3$

$b=5$

Therefore, the coordinates of B are (-5,5).

6 0

4 years ago