A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5
Using the slope-intercept form, the slope is
2
/5 2/5.M=
25
Answer:
1
Step-by-step explanation:
Hi!
First we need to translate 2 units down. That means we need to subtract 2 from the y value. So now we have (-1,1).
For a 270 degree counterclockwise rotation the rule is to go from (x,y) to (y,-x)
So now we have (1,1). Since they're only asking for the x value, the answer is 1.
This is not picture so I don’t know what to do !
Answer: Option(D) is the correct option
Explanation:
Natural pairings defines coupling of data sets or sample is possible to take place in a particular condition naturally.These samples depend on each other for matching.
According to the question ,cholesterol level of 90 men is being assessed prior and after treatment takes place.Thus,same 90 men are going through drug testing in natural pair form and showing sample dependency before and afterwards of treatment.Thus, further analysis is based upon natural paired data.
Other options are incorrect because sample in the question are not independent due to the link between them and they do persist natural pairing with each other.Thus, the correct option is option(D).
