All categories

2 years ago

I need help with this

Mathematics

1 answer:

Doss [256]2 years ago

3 0

$\text{Apply Pythagorean theorem,}\\\\~~~~x^2 = 6^2 +8^2\\\\\implies x = \sqrt{6^2 +8^2}\\\\\implies x = \sqrt{36 +64}\\\\\implies x =\sqrt{100}\\\\\implies x = 10~~ \text{units.}$

You might be interested in

A sports ball has a diameter of 12 cm. Find the volume of the ball. Round your answer to 2 decimal places, and use 3.14 as an ap

Kitty [74]

A ball is a shpere and the formula for calculating the volume of a sphere is:

$V = \frac{4}{3} \pi r^{3}$

The formula in our case:

$V = \frac{4}{3}*3,14*6^{3}$

$V = \frac{4}{3} * 3,14 * 216$

$V = \frac{12,56}{3} * 216$

$V = 4,19 * 216$

$V = 905,04~cm^{3}$

Answer:

$\boxed{\bf~The~volume~of~the~ball~is~905,04~cm^{3} }$

Hope it helped,

BioTeacher101

7 0

3 years ago

Which function below has the largest slope?

OleMash [197]

Bruh, this must be so confusing oh well maybe when i actually get to learn this stuff it may be easier for me then ok

7 0

4 years ago

Find the equation of the line shown

solniwko [45]

Answer:

$y=-\frac{1}{4}x+2$

Step-by-step explanation:

We will use the point slope formula: $y=mx+b$

We will start by finding the slope( $m$ ).
The formula for slope is

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

So if we just choose 2 random points on the line:

I choose (0,2) and (4,1), we get:

$\frac{1-2}{4-0} = \frac{-1}{4}$

That's our slope.

Next we need to find the y-intercept( $b$ ). We can find that by looking at the graph. It is where x=0. So in this case y=2 when x=0.

So in point-slope form the equation is:

$y=-\frac{1}{4}x+2$

7 0

3 years ago

I need help with A-G,I,L,N<br>I hope yall have a merry Christmas

KonstantinChe [14]

Format of my answer:

[Problem letter] Parallel Lines

- Converse / Reason

!! I am not sure which / what converses you are using, but I gave the reasoning for it. If you see something similar, use the converses you know !!

[a] j & k

- If two lines intersected by a transversal form congruent alternate interior angles, then the lines are parallel

[b] m & n

- If angles are supplementary in this placement, the lines are parallel

[c] l & n

- If angles are equal when they are corresponding, the lines are parallel

[d] l & m

- If two angles that are congruent are vertical, the lines are parallel

[e] j & k

- If two lines intersected by a transversal form congruent corresponding angles, then the lines are parallel

[f] l & n

- If angles are supplementary in this placement, the lines are parallel

[g] l & n

- If two angles that are congruent are vertical, the lines are parallel

[h] -------

[i] l & n

- If two angles that are congruent are vertical, the lines are parallel

[j] -------

[k] -------

[l] j & k

- If two lines intersected by a transversal form congruent corresponding angles, then the lines are parallel

[m] -------

[n] j & k

- If angles are supplementary in this placement, the lines are parallel

[o] -------

-> See attached for more information

Have a nice day! - hopefully these are mostly correct, been awhile since I've done this

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0

2 years ago

Multiply the binomials (2x 6)(x-1)

Vlad [161]

(2x 6)(x-1)=0 happy to help :)

8 0

3 years ago