All categories

1 year ago

Can anyone help me with this please

Mathematics

1 answer:

deff fn [24]1 year ago

4 0

Answer:

RPM 1388.889

Horsepower 366.802

Step-by-step explanation:

We do not need to solve the equation for y = 0, which is nice. We can go directly to finding the maximum.

The maximum or minimum of ax^2+bx+c is always at x=-b/2a

with b = 25/45 and a = -1/5000 we get

x = -25/45 / (-2/5000) = 5/9 * 2500 = 12500/9 ≈ 1388.889

Now we only need to put that x into the equation (ideally in form of 12500/9 for accuracy) and we get the horsepower of ~366.802

You might be interested in

Please help! (I'll give brainliest to the first right answer)

eduard

Answer:

1/2: the fourth quadrant

3/4:"Q1: 4,5" "Q2: 4,-1" "Q3: -2,-3" "Q4: 5, -2"

Step-by-step explanation:

hope this helps!

5 0

2 years ago

suppose Richard walks one kilometer every 10 minutes how many meters are there can you walk in an hour at this new rate

Ipatiy [6.2K]

One kilometer is 1000 meters. One hour is 60 minutes, or six segments of 10 minutes each. If you can walk 1000 meters in 10 minutes, you can walk 6000 in an hour (that is REALLY fast, by the way)

3 0

3 years ago

3x + 4 divided by 2 = 9.5

Sergeu [11.5K]

2.5 is your answer because first we divide the numbers then subtract 2 from both sides and simplify

8 0

1 year ago

Read 2 more answers

Harish

Artist 52 [7]

Answer:

Step-by-step explanation:

Distance traveled in $1\frac{4}{5}$ hours = $\frac{3}{10}$

Distance traveled in 1 hour = $\frac{3}{10}$ ÷ $1\frac{4}{5}$

$=\frac{3}{10}$ ÷ $\frac{9}{5}$

$= \frac{3}{10}*\frac{5}{9}\\\\=\frac{1}{2}*\frac{1}{3}\\\\=\frac{1}{6}$

distance traveled in 3 1/5 hours = $\frac{1}{6}*3\frac{1}{5}$

= $=\frac{1}{6}*\frac{8}{5}\\\\=\frac{1}{3}*\frac{4}{5}\\\\=\frac{4}{15}$

5 0

2 years ago

Prove: The midsegment between sides Line segment AB and Line segment BC is parallel to side Line segment AC.

Allushta [10]

CD in the middle
have a nice day sir/maam

3 0

3 years ago