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2 years ago

7

Which of the following pairs of values are NOT equal in a normal distribution curve?

1 answer:

qaws [65]2 years ago

5 0

The mean, median, and mode of a completely normal distribution will all have the same value, represented graphically by the top of the curve. The correct option is C.

<h3>What is a normal distribution?</h3>

The mean, median, and mode of a completely normal distribution will all have the same value, represented graphically by the top of the curve. The normal distribution is often known as the bell curve because the probability density graph resembles a bell.

The option that is not true for the normal distribution is the value of the mean and the height of the density curve at its lowest are not equal.

Hence, the correct option is C.

Learn more about Normal Distribution:

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Please help I still do not understand these questions

solniwko [45]

Answer:

m = 2/5

Step-by-step explanation:

easy

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3 years ago

Amare runs 1/10 mile in 2/3 minutes. What is his speed in miles per minute

liraira [26]

Answer:

6 2/3 minutes

Step-by-step explanation:

Amare runs 1/10 mile in 2/3 minutes

Therefore his speed in miles per minutes clean be calculated as follows

= 1/10, the denominator here is 10

= 10 × 2/3

= 20/3

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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

What is the solution to the system of equations?

s344n2d4d5 [400]

Answer:

(3,2)

Step-by-step explanation:

Here's your given:

y = 4x - 10

y = 2

Because they both equal y, that means they equal each other:

2 = 4x - 10

Add 10 on both sides:

12 = 4x

Then, divide 4 on both sides:

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This represents the x coordinate.

Normally you would put this value into one of the equations to figure out y, but they already gave us that in the beginning:

y = 2

This represents the y coordinate.

Put the two values together to get: (3,2)

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3 years ago

Simplify the expressions by distributing the negatives and combining like terms

Illusion [34]

Answer:

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Step-by-step explanation:

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3 years ago