Simplifying
x + 6 = 3x + -14
Reorder the terms:
6 + x = 3x + -14
Reorder the terms:
6 + x = -14 + 3x
Solving
6 + x = -14 + 3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3x' to each side of the equation.
6 + x + -3x = -14 + 3x + -3x
Combine like terms: x + -3x = -2x
6 + -2x = -14 + 3x + -3x
Combine like terms: 3x + -3x = 0
6 + -2x = -14 + 0
6 + -2x = -14
Add '-6' to each side of the equation.
6 + -6 + -2x = -14 + -6
Combine like terms: 6 + -6 = 0
0 + -2x = -14 + -6
-2x = -14 + -6
Combine like terms: -14 + -6 = -20
-2x = -20
Divide each side by '-2'.
x = 10
Simplifying
x = 10
Answer:
5
Step-by-step explanation:
The sequence is a "/2 sequence", which means each number equals half of the previous one.
40 is half of 80.
20 is half of 40.
10 is half of 20.
5 is half of 10.
Hope it helped,
BioTeacher101
Answer:
AEB =43
Step-by-step explanation:
The two angles form a straight line so they add to 180 degrees
AED + AEB = 180
137+AEB = 180
AEB = 180-137
AEB =43
Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, 
is 37°. We can see from the diagram that 
would be 
143°.
Also, the new bearing is N 25°E. So, 
would be 25°.
Now we can find 
. As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
(4,1)
Step-by-step explanation:
x+y=5
x- y=3
Add the equations together to eliminate y
x+y=5
x- y=3
--------------------
2x = 8
Divide each side by 2
2x/2 = 8/2
x = 4
Now we can find y
x+y = 5
4+y = 5
Subtract 4 from each side
4+y-4 = 5-4
y =1
