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anzhelika [568]
2 years ago
8

Please i will give you 23 points\

Mathematics
1 answer:
worty [1.4K]2 years ago
4 0

Answer:

see photo for detailed analysis

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I think this is it I did this when I was in 5th grade so I don't remember that much might wanna check with an adult.
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Find the value of the polynomial-x -x^2+3x+2 what x =-4
Lelechka [254]
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The half life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
Veronika [31]

Using an exponential function, it is found that:

a) N(t) = 75(0.5)^{\frac{t}{3.8}}

b) 37.5 grams of the gas remains after 3.8 days.

c) The amount remaining will be of 10 grams after approximately 11 days.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

Item a:

We start with 75 grams, and then work with a half-life of 3.8 days, hence the amount after t daus is given by:

N(t) = 75(0.5)^{\frac{t}{3.8}}

Item b:

This is N when t = 3.8, hence:

N(t) = 75(0.5)^{\frac{3.8}{3.8}} = 37.5

37.5 grams of the gas remains after 3.8 days.

Item c:

This is t for which N(t) = 10, hence:

N(t) = 75(0.5)^{\frac{t}{3.8}}

10 = 75(0.5)^{\frac{t}{3.8}}

(0.5)^{\frac{t}{3.8}} = \frac{10}{75}

\log{(0.5)^{\frac{t}{3.8}}} = \log{\frac{10}{75}}

\frac{t}{3.8}\log{0.5} = \log{\frac{10}{75}}

t = 3.8\frac{\log{\frac{10}{75}}}{\log{0.5}}

t \approx 11

The amount remaining will be of 10 grams after approximately 11 days.

More can be learned about exponential functions at brainly.com/question/25537936

4 0
2 years ago
Construct a quadrilateral MINT such that MI= 5cm, IN = 6cm, NT = 7cm, TM=3cm and MN =9cm
Tems11 [23]

From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral

MINT can be drawn as shown in the attached image.

<h3>What are the steps for the construction of MINT?</h3>

The given dimensions of the quadrilateral MINT are;

MI = 5 cm

IN = 6 cm

NT = 7 cm

TM = 3 cm

MN = 9 cm

The side MN is a diagonal of MINT, therefore;

ΔMIN, and ΔMTN are triangles with a common base = MN

The steps to construct MINT are therefore;

  • Step 1; Draw the line MN = 9 cm.

  • Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.

  • Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.

  • Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.

  • Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.

  • Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.

Please find attached the drawing (showing the construction arcs) of the

quadrilateral MINT created with MS Word.

Learn more about types of geometric construction here:

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6 0
2 years ago
I need help with this problem PLEASE HELP
xxTIMURxx [149]

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

<h3>How to Determine the Range and the Domain of a Function?</h3>

In any given graph that represents a function, the possible set of domain values are plotted on the x-axis (horizontal axis), while the possible set of corresponding range values are plotted on the y-axis (vertical axis).

Thus, the set of x-values (input values) on a graph is the domain of the function while the set of y-values (output values) is the range of the function.

In the given graph, the set of x-values are: -5, -3, -1, and 1.

The set of y-values are: -5, -3, -1, and 1.

Therefore:

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

Learn more about the domain and range of a function on:

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7 0
2 years ago
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