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miv72 [106K]
1 year ago
8

100 POINTS !!! Find the axis of symmetry and the vertex of the graph of y = 6x2 − 24x + 11. x = 2; (2, −13) x = 4; (4, 11) x = −

2; (−2, 83) x = −4; (−4, −11)
Mathematics
2 answers:
xxTIMURxx [149]1 year ago
7 0

Let's see

\\ \rm\rightarrowtail y=6x^2-25x+11

Graph attached

  • vertex(-2,-13)

Axis of symmetry

  • x=-2

creativ13 [48]1 year ago
3 0

Answer:

axis of symmetry: x = 2

vertex:  (-2, 13)

Step-by-step explanation:

<u>Given function</u>

\sf y=6x^2-24x+11

<u>Vertex form</u>

\sf y=a(x-h)^2+k
where (h, k) is the vertex

Expand vertex form:

\sf \implies y=ax^2-2ahx+ah^2+k

Compare coefficients of expanded vertex form with given function:

coefficient of \sf x^2:  

⇒ a = 6

coefficient of \sf x:  

⇒ -2ah = -24

⇒ ah = 12

⇒ 6h = 12

⇒ h = 2

constant:

⇒ \sf ah^2+k=11

⇒ \sf 6 \cdot 2^2+k=11

⇒ \sf 24+k=11

⇒ \sf k=-13

<u>Vertex</u>

Vertex = (2, -13)

<u>Axis of symmetry</u>

Axis of symmetry is when x = h

Therefore, axis of symmetry is x = 2

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Hi Vanessa


3x -1/9 (27) =18

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