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Sergeeva-Olga [200]
3 years ago
9

I need help with this question. I cant find the surface area of this square pyramid. Please help me.

Mathematics
1 answer:
docker41 [41]3 years ago
4 0
25 bc 5 times 5 is 25
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Determine all real values of p such that the set of all linear combination of u = (3, p) and v = (1, 2) is all of R2. Justify yo
Rama09 [41]

Answer:

p ∈ IR - {6}

Step-by-step explanation:

The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2

is all R2 ⇔

u\neq 0_{R2}      

v\neq 0_{R2}

And also u and v must be linearly independent.

In order to achieve the final condition, we can make a matrix that belongs to R^{2x2} using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.

Let's make the matrix :

A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]

We used the first vector ''u'' as the first column of the matrix A

We used the  second vector ''v'' as the second column of the matrix A

The determinant of the matrix ''A'' is

Det(A)=6-p

We need this determinant to be different to zero

6-p\neq 0

p\neq 6

The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that p\neq 6

We can write : p ∈ IR - {6}

Notice that is p=6 ⇒

u=(3,6)

v=(1,2)

If we write 3v=3(1,2)=(3,6)=u , the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.

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3. Find the volume of a cylinder with a base area of
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Answer:

Its B

Step-by-step explanation:

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The origin of this word is latin: because of this it also has the plural of "bimillennia"   <span />
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Simplify the following: 6i^3 +4j^2 -6i<br> Please show work
Vadim26 [7]

Answer:

Concept: Vectors

  1. I think the confusion here might be the usage of i and j
  2. Just to let you know, i=x and j=y
  3. So let's use that fact to conceptualize this
  4. 6x^3+4y^2-6x
  5. We can simplify by applying a common factor
  6. 2(x^3+2y^2-3x)
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