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2 years ago

What is the area of this figure? Please help.

Mathematics

1 answer:

Ad libitum [116K]2 years ago

8 0

The area of the composite figure can be found by summing the whole area that made up the figure. Therefore, the area of the figure is 213.5m²

<h3>Area of a composite figure</h3>

The area of the composite figure is the sum of the area of the whole figure.

Therefore, the composite figure can be divided into 2 triangles and two rectangles.

Hence,

area of triangle1 = 1 / 2 × 10 × 13 = 65 m²

area of the triangle2 = 1 / 2 × 15 × 7 = 52.5 m²

area of the rectangle1 = 8 × 3 = 24 m²

area of rectangle2 = 7 × 6 = 42 m²

area of rectangle3 = 5 × 6 = 30 m²

Therefore,

area of the composite figure = 65 + 52.5 + 24 + 42 + 30 = 213.5 meters squared

learn more on area here: brainly.com/question/27744042

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a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

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Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

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$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

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