Question

Factorise and divide: (3y^8 - 4y^6 + 5y^4) ÷ y^3

Answer 1

Answer: 3y^4 - 4y^2 + 5

Step-by-step explanation:

Im fairly sure this is the answer but again i dont know

3y^8 = 3 x y x y x y x y x y x y x y x y

4y^6 = 4 x y x y x y x y x y x y

5y^4 = 5 x y x y x y x y

=  

(3×y×y×y×y×y×y×y×y)−(4×y×y×y×y×y×y)+(5×y×y×y×y)

                                         y^4

= y^4 [(3×y×y×y×y)−(4×y×y)+(5)]

​

=  3y^4 - 4y^2 + 5