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Degger [83]
3 years ago
5

Very much need some help ASAP !!

Mathematics
1 answer:
Rudiy273 years ago
4 0

Answer:

D

Step-by-step explanation:

It cannot be Option A because the values are halve and there is nothing to distribute to them to make the values equal.

It's not option C because if you distribute 2y to each term in the parenthesis

you get -4y^{5}  + 6y³  + 4y².   But where is the 8y² and -2y?

While Option B is equivalent, you can factor it out more and find the common factor of -2 to distribute among them as shown in option D

It is option D because distributing the -2y to each term solves to

-4y^{5}  + 6y³   +  8y²  -2y.

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Would you rather 36 spherical bottles with radi = 4.57 or three 12-packs of cans if each box is 15inx5inx4.4in
grigory [225]

Answer:

  36 bottles

Step-by-step explanation:

Each spherical bottle will have a volume of ...

  V = (4/3)πr³ = (4/3)π(4.57³) = 399.8 . . . . cubic inches

Each box (12-pack?) will have a volume of ...

  V = LWH = (15 in)(5 in)(4.4 in) = 330 in³

This is a smaller volume than even one spherical bottle, so 36 bottles will have the larger volume.

5 0
4 years ago
What are the common factors of 60 and 72?
ddd [48]
Answer: 1, 2, 3, 4, 6, 12

Calculation/Explanation:

Common factors are factors that both the numbers, in this case, 60 and 72, have in common. The factors listed above are all factors shared by 60 and 72.
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3 years ago
(–9) • (8) – (9) • (–9)
elena-s [515]

Answer:

10

Step-by-step explanation:


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4 years ago
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Sindrei [870]
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6 0
3 years ago
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Triangle abc is similar to triangle def solve for both unknown sides
Serhud [2]

Given:

Triangles ABC and DEF are similar triangles.

AB = 6 m, BC = 16 m, CA = 15 m, DE = x, EF = 32 m, FD = y

To find:

The values of unknown sides, i.e., x and y.

Solution:

We know that the corresponding parts of similar triangles are proportional and triangles ABC and DEF are similar triangles, so

\dfrac{AB}{DE}=\dfrac{BC}{EF}=\dfrac{CA}{FD}

\dfrac{6}{x}=\dfrac{16}{32}=\dfrac{15}{y}

\dfrac{6}{x}=\dfrac{1}{2}=\dfrac{15}{y}

Now,

\dfrac{6}{x}=\dfrac{1}{2}

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Similarly,

\dfrac{1}{2}=\dfrac{15}{y}

1\times y=15\times 2

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Therefore, the measure of unknown sides are x = 12 m and y = 30 m.

7 0
3 years ago
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