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Degger [83]
3 years ago
5

Very much need some help ASAP !!

Mathematics
1 answer:
Rudiy273 years ago
4 0

Answer:

D

Step-by-step explanation:

It cannot be Option A because the values are halve and there is nothing to distribute to them to make the values equal.

It's not option C because if you distribute 2y to each term in the parenthesis

you get -4y^{5}  + 6y³  + 4y².   But where is the 8y² and -2y?

While Option B is equivalent, you can factor it out more and find the common factor of -2 to distribute among them as shown in option D

It is option D because distributing the -2y to each term solves to

-4y^{5}  + 6y³   +  8y²  -2y.

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steposvetlana [31]

Answer:

It would be the first graph, because if you look at the points on your graph the first one is (0,1), the the next one is (5,2), and so on so forth, that makes your answer the first graph, because that table is showing you the points that are marked

Step-by-step explanation:

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Basketball shoes are on sale for 22% off. What is the regular price if the sale price is $42?
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Answer:

x =53.85

Step-by-step explanation:

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Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
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Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

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3 years ago
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