Question

Factor to find the zeros of the function: y = 8x2 + 8x − 96

Answer 1

$y=8x^2+8x-96\\\\8x^2+8x-96=0\ \ \ |:8\\\\x^2+x-12=0\\\\x^2+4x-3x-12=0\\\\x(x+4)-3(x+4)=0\\\\(x+4)(x-3)=0\iff x+4=0\ \vee\ x-3=0\\\\\boxed{x=-4\ \vee\ x=3}$