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inna [77]
3 years ago
5

Pete is 4 times the age of Myrtle. 2 years ago, Pete was 8 times as old as Myrtle. How old are they?

Mathematics
1 answer:
otez555 [7]3 years ago
7 0

Answer:

one How old is Myrtle to being with?

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Ve. .
Alinara [238K]

Answer:

They are (6, 1) or (3, 2).

Step-by-step explanation:

The factor pairs of 6 are 1×6 and 2×3

So the parallelogram (height by length) could be:

1 by 6

2 by 3

3 by 2

6 by 1.

3 0
3 years ago
PLEASE ANSWER QUICK Part A: If (62)x = 1, what is the value of x? Explain your answer. (5 points) Part B: If (60)x = 1, what are
ANTONII [103]

Answer:

The first one is 0, the second one is ARN (All real numbers)

Step-by-step explanation:

1. Anything raised to the "zeroth" power is always 1

2. Because 7 is being raised to the zeroth power, the number inside the parentheses becomes 1. Now x can equal anything, 1 times itself will always equal 1, no matter how many times you multiply them.

8 0
3 years ago
Read 2 more answers
Do you know how to use the Pythagorean identity?
goblinko [34]

The Pythagorean theorem or identity is given by

  • H²=P²+B²
  • P²=H²-B²
  • B²=H²-P²

Where

  • B is base of right angle traingle
  • H is Hypotenuse
  • P is perpendicular
8 0
2 years ago
What is 622,119 rounded to the nearest hundred?
adell [148]

Answer:

The answer is 622,100

Step-by-step explanation:

The answer is 622,100 because the 1 in the tens place is smaller then a 5 so it gets rounded down to 0.

So, the answer is 622,100

Hope this helps! :)

6 0
3 years ago
Solve the rational function of (check image) and check for extraneous solutions
Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

\frac{5}{x}=\frac{4x+1}{x^2}

Solving the rational function

\frac{5}{x}=\frac{4x+1}{x^2}

Apply fraction across multiply: if \frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5x^2=x\left(4x+1\right)

Subtract x(4x+1) from both sides

5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)

Simplify

5x^2-x\left(4x+1\right)=0

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x=0\quad \mathrm{or}\quad \:x-1=0

Thus, the solution to the equation is:

x=0,\:x=1

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0
3 years ago
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