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xeze [42]
2 years ago
5

Find the mean absolute deviation for the data set. {3, 5, 6, 3, 2, 2, 1, 0, 0, 4, 7, 4, 5, 5, 6}

Mathematics
1 answer:
Ratling [72]2 years ago
5 0

Answer:

0.50

Step-by-step explanation:

The mean = 3 + 5 + 6+ 3 +2+ 2+ 1+0+ 0+ 4+ 7+ 4+ 5 + 5 + 6) / 15

= 53/15

= 3.533

Difference of values from the mean:

<u> n </u>    <u> n - 3.533</u>  (Absolute value)

3         0.533

3         0.533

6         2.467

3         0.533

2          1.533

2          1.533

1           2.533

0          3.533

0          3.533

4           0.467

4           0.467

5            1.467

5            1.467

6            2.567

7             3.467

Totals:  

53         26.533

So the M.A.D. = 26.533 / 53 =  0.50  

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grandymaker [24]

Answer:A=X x=8

B=x X=9

C=x X=10

Step-by-step explanation:

8 0
3 years ago
DOES ANYONE KNOW THE ANSWER?????????
givi [52]

There's only information to answer question C.

We can only know that 32 marbles were chosen. (yellow and black)

Why?

To answer the first two questions (a and b), we need to know the total number of marbles, so, we can only answer the last question (c).

We know that 7/10 of the 20 yellow marbles were chosen.

So, calculating we have:

\frac{7}{10}*20=14(yellow)

Also, we know that 18 black marbles were chosen, so, the total of marbles chosen is equal to 32 (yellow marbles and black marbles)

TotalMarbles=14(yellow)+18(black)=32marbles

Have a nice day!

8 0
3 years ago
St lies on the coordinate plane with s located at (3.2). The midpoint of dt is z(3,9) state the location of the endpoint T thank
77julia77 [94]

Answer:

T = (3,16)

Step-by-step explanation:

The midpoint formula is just another version of the pythagorean theorem, and it states that the midpoint between (x1,y1) and (x2,y2) is \left(\frac{x_1+x_2}{2}\right),\:\left(\frac{y_1+y_2}{2}\right)

Substituting what we know:

endpoint S is (3,2) and endpoint T is (x2,y2)

Midpoint Z is (3,9). We will apply the formula -- backwards.

\left(\frac{3+x_2}{2}\right)=3, solving with algebra we get x2 = 3

So the x-coordinate of endpoint T is 3.

\left(\frac{2+y_2}{2}\right)=9\quad, solving with algebra, we get y2 = 16.

So the y-coordinate of endpoint T is 16.

So the location of endpoint T is (3,16)

4 0
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Lerok [7]
What is the question to this explanation?
5 0
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marishachu [46]

Answer:

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Step-by-step explanation:

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8 0
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