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PtichkaEL [24]
3 years ago
13

Y=2x+4 I need what the graph would look like. Please help me!

Mathematics
2 answers:
Rasek [7]3 years ago
8 0

Answer:Hey there! Here's what the graph would look like!

Step-by-step explanation:

Veseljchak [2.6K]3 years ago
6 0

Answer: I attached a picture of the graph

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What is the surface area of the following prism?
Stolb23 [73]

Answer:

102cm²

Step-by-step explanation:

Surface Area = BH +Lp

B is the base area

H is the height of the Prism

L is the slant height

p is t perimeter of its base

B =1/2 ×3×4

B= 6cm²

H = 7cm

L = 5cm

P = 3cm+4cm+5cm

P = 12cm

Substitute

TSA = 6(7)+5(12)

TSA = 42+60

TSA = 102cm²

Hence the total surface area of the shape is 102cm²

5 0
3 years ago
Need help asap!!!!!!!!!
Simora [160]

Answer:

b

Step-by-step explanation:

its the only answer with consistent values that go up

4 0
3 years ago
Read 2 more answers
You have a bucket with 7 green ping pong balls, 13 black ping pong balls, and 9 red ping pong balls.
elixir [45]

Answer:

Step-by-step explanation:

A. In each drawing, the odds of choosing green is 7 / (7 + 13 + 9) = 7/29

with replacement, the odds in each drawing are the same

7/29•7/29•7/29 = 7³/39³ = 343 / 24,389

B.

Odds of drawing all non black balls is the sum of odds of drawing the following possible patterns

 ggg  +   ggr   +   grg   +   rgg  +   rrg   +    rgr   +    grr   +   rrr

(7•6•5 + 7•6•9 + 7•9•6 + 9•7•6 + 9•8•7 + 9•7•8 + 7•9•8 + 9•8•7) / 29•28•27 = 3,360/21,924

3 0
3 years ago
The altitude of this cylinder is-----------------. line BC, segment GC, BC or ray CB there is a b on top of cylinder in center a
VikaD [51]

The altitude of a shape or a polygon can be determined by drawing a perpendicular line from the base to the top most part of the polygon. In this case, the altitude is the segment BC where the ends are on the topmost of the cylinder and the base of the cylinder. 
8 0
4 years ago
Anyone know 112.5 ft. in fraction form ?
Keith_Richards [23]
.5 is really just 1/2 as a fraction so:
112 1/2 is fraction form
6 0
4 years ago
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