We know that ∠1 equals ∠3, from that we can find x:
The sum of ∠1 and ∠2 must equal 180°:
Since we already know x, we can solve for y:
Result: x=10, y=6
What 2 numbers multiply to get 40 and add to get -14
-10 and -4
(x-4)(x-10)=0
set to zero
x-4=0
x=4
x-10=0
x=10
x=4 and 10
step 1: open up the brackets ( rmb to flip the signs )
step 2: bring 'a' to one side and the numbers to the other
6a + 34 = -3(-2a + 8)
6a + 34 = 6a - 24
6a - 6a = -24 - 34
0 = - 58
the final ans is kind of weird but here's my solution :))
Answer:
I believe the answer is option B because I am right. Haha trust me.
Step-by-step explanation:
Answer:
y ≥ 3x -1; x +3y ≤ 6
Step-by-step explanation:
Both lines are solid, so the only viable choices are those with "or equal to" in the comparison operators: the 2nd and 4th choices.
The line with a slope of +3 is shaded <u><em>above</em></u> the line, so that will correspond to the inequality ...
y ≥ 3x -1 . . . . . . . . . . found only in the 4th choice.
