we know its diameter is 12, thus its radius must be half that, or 6.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6 \end{cases}\implies A=\pi 6^2\implies A=36\pi \implies A\approx 113.097](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%206%5E2%5Cimplies%20A%3D36%5Cpi%20%5Cimplies%20A%5Capprox%20113.097)
<u><em>Answer: A. -14. x=-14 and -14=x. *The answer should be the negative sign.*</em></u>
Step-by-step explanation:
subtraction property of equality is subtracting the same number from both sides of an equation does not change the equation.
switch sides of an equation.
x+19=5
subtract by 19 both sides of an equation.
x+19-19=5-19
simplify.
19-5=14
x=-14 and -14=x
Hope this helps!
Thanks!
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It would be 159 parts. This is because 1116/7 is 159.42 and technically a part can only be a whole number. So it would be 159 parts.
Answer:
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Step-by-step explanation:
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<h3><u>Out of the four options, the letter B is a function.</u></h3>
A function cannot have an x value with two different listed y terms.
B is the only option that does not repeat x terms.
