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2 years ago

Use the drawing tools to form the correct answer on the graph. Plot function f on the graph. f(x)= 3, -9

1 answer:

6 0

The equation of the function f with solution 3, -9 is x²+6x-27 and the graph of this equation with the use of drawing tools is attached below.

<h3>What is the definition of a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

A function has to be plot which has the value of f(x) as 3 and -9. Here, 3 and -9 are the solution of the function. Thus,

x=3

x-3=0

The second solution is,

x=-9

x+9=0

Multiply both factor for the function as,

f(x)=(x-3)(x+9)

f(x)=x²+9x-3x-27

f(x)=x²+6x-27

This is the required function. The graph of this function is attached below.

Thus, the equation of the function f with solution 3, -9 is x²+6x-27 and the graph of this equation with the use of drawing tools is attached below.

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You might be interested in

Write the sum as a product simplify the product-2 + -2 + -2 + -2 equals

yuradex [85]

-2+-2+-2+-2
-4+-4
=-8
hope this helps:)

6 0

3 years ago

Five to the power of five (16 power of 2 times 5 to the power of 3)power 3

11Alexandr11 [23.1K]

Answer:

1.024x10^17

Step-by-step explanation:

5^5(16^2x5^3)^3

find the 5^5

3125(16^2x5^3)^3

distribute the power of 3 into the parentheses

3125(16^6x5^9)

multiply

3125(16777216x1953125)

1.024x10^17

8 0

3 years ago

A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de

gregori [183]

a= μ-3.16*σ , b= μ+3.16*σ if each fish caught is equally likely to be any one of these 4 distinct types.

<h3>What is meant by Chebyshev inequality?</h3>

Chebyshev's inequality is a probability theory that ensures that, over a vast range of probability distributions, no more than a particular proportion of values would be present within a selected limits or range as from mean. In other words, only a certain fish caught will be discovered within a given range of the distribution's mean.

The formula for which no more than a particular number of values can exceed is 1/K2; in other words, 1/K2 of a distribution's values can be more than or equal to K standard deviations away from the distribution's mean. Furthermore, it asserts that 1-(1/K2) of a distribution's values must be within, but not include, K standard deviations of the distribution's mean.

How to solve?

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y = the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 → 1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90 → 1- σ²/(σ²+λ²)= 1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

In order to learn more about Chebyshev inequality, visit:

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4 0

1 year ago

What decimal is equivalent to negative 3 over 8

timurjin [86]

Answer:

-9 / 24

Step-by-step explanation:

<u>Step 1: Find an equivalent to -3/8</u>

(-3*3) / (8*3)

<em />

Answer: -9 / 24

7 0

3 years ago

Read 2 more answers

Please help me :)))))

svetoff [14.1K]

Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi

Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi

Note: the same issue comes up as before in part a)

============================================================

Part c)

Answer: sqrt(19pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi

8 0

3 years ago

Read 2 more answers