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Dovator [93]
3 years ago
15

Find a cofunction with the same value as the given expression. csc 52°

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
5 0
To find a cofunction with the same value as the expression csc 52*, you would use the formula like this.  csc (x) = sec (90-x). So if you use csc(52) that equals sec(90-52). This in turn, equals sec(38). So the answer is B.
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Is the relation shown in the table below a function? Explain.
jek_recluse [69]

Answer

No

Step-by-step explanation:

it is not a function because 9 and three are a pair but so are 27 and 3. that makes it not a function

4 0
3 years ago
g The average midterm score of students in a certain course is 70 points. From the past experience it is known that the midterm
spayn [35]

Answer:

0.98 = 98% probability that the average midterm score of these students is at most 75 points.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The average midterm score of students in a certain course is 70 points.

This means that \mu = 70

29 students are randomly selected and the standard deviation of their scores is found to be 13.15 points.

This means that \sigma = 13.15, n = 29, s = \frac{13.15}{\sqrt{29}} = 2.44

Find the probability that the average midterm score of these students is at most 75 points.

This is the pvalue of Z when X = 75. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{75 - 70}{2.44}

Z = 2.05

Z = 2.05 has a pvalue of 0.98.

0.98 = 98% probability that the average midterm score of these students is at most 75 points.

8 0
3 years ago
Translate the followingame phrase into an algebraic expression using the variable w. Do not simplify.
katrin [286]

Answer:

2w+2(2w-7)

Step-by-step explanation:

the first 2w is the length of the two widths, and the (2w-7) is the length of the length, and we multiply by two because there are two sides.

4 0
3 years ago
??????((((((((??????????
mart [117]

Answer:

G. 17.3

solution:

5 0
3 years ago
Dan tan 31 miles more than Jennifer last week. Dan ran 138 miles. How many miles did Jennifer run?
PtichkaEL [24]
Solution:
138-31= 107 miles
7 0
3 years ago
Read 2 more answers
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