Answer:
180 Vertical angles are opposite angles that share only a vertex. Since ∠3 is adjacent to both ∠1 and ∠2, this means that ∠3 shares a side and vertex with both of these angles.
This means that ∠3 and ∠1 form a straight line; this makes them a linear pair, which makes their sum 180°.
Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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Answer:
2
Step-by-step explanation:
rounded down
Answer:
-5
Step-by-step explanation:
f(-2) means that -2 is going to be our input in this function.
To solve this, simply substitute -2 for x in the expression given.
If f(x) = 3x+1, then f(-2) = 3(-2) + 1
3(-2)+1 = -6+1 = -5
Hope this helped!
Answer:
See attachment
Step-by-step explanation:
