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3 years ago

How do you do this question?

Mathematics

1 answer:

Lisa [10]3 years ago

7 0

Answer:

Correct integral, third graph

Step-by-step explanation:

Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.

Given : ∫ tan²(θ)sec²(θ)dθ

Applying u-substitution : u = tan(θ),

=> ∫ u²du

Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1

Substitute back u = tan(θ) : tan^2+1(θ)/2+1

Simplify : 1/3tan³(θ)

Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.

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Dear Garden Designer,

guapka [62]

Answer:

Step-by-step explanation:MATHEMATICAL GOALS

This lesson unit is intended to help assess how well students are able to interpret and use scale

drawings to plan a garden layout. This involves using proportional reasoning and metric units.

COMMON CORE STATE STANDARDS

This lesson relates to the following Standards for Mathematical Practices in the Common Core State

Standards for Mathematics, with a particular emphasis on Practices 1, 3, 4, 5, and 6:

1. Make sense of problems and persevere in solving them.

2. Reason abstractly and quantitatively.

3. Construct viable arguments and critique the reasoning of others.

4. Model with mathematics.

5. Use appropriate tools strategically.

6. Attend to precision.

8. Look for and express regularity in repeated reasoning.

This lesson gives students the opportunity to apply their knowledge of the following Standards for

Mathematical Content in the Common Core State Standards for Mathematics:

7.G: Draw, construct, and describe geometrical figures and describe the relationships between

them.

Solve real-life and mathematical problems involving angle measure, area, surface area,

and volume.

7.EE: Solve real-life and mathematical problems using numerical and algebraic expressions and

equations.

7.RP: Analyze proportional relationships and use them to solve real-world and mathematical

problems.

INTRODUCTION

This lesson unit is structured in the following way:

• Before the lesson, students work individually on a task designed to reveal their current levels of

understanding. You review their responses and create questions to help them improve their work.

• At the start of the lesson, students reflect on their individual responses, before producing a

collaborative improved solution to the task. Then, in the same small groups students analyze

sample responses. They then discuss as a whole-class the methods they have seen and used.

• In a follow-up lesson, students reflect on their work. If time allows, an extension task is available.

MATERIALS REQUIRED

• Each student will need a copy of Design a Garden and Garden Plan, some blank paper, a miniwhiteboard, pen, and eraser, and the How Did You Work? questionnaire. The Garden Plan should

be copied at exactly 100% scale so the measurements are accurate. If this is not possible,

photocopy the rules on S-3, one rule per student, which should then match the Garden Plan

measurements. It will be useful to have spare copies of the Garden Plan.

• Each small group of students will need a new copy of the Garden Plan, the Assistants’ Methods, a

glue stick, felt-tipped pen, and a sheet of poster paper. For the optional extension Mandy’s Second

Email will be needed. Provide short rules, meter rules, string, protractors, scissors, glue, card,

plain paper, graph paper, and colored pencils for students who choose to use them.

TIME NEEDED

20 minutes before the lesson, a 110-minute lesson (or two 60-minute lessons), and 10 minutes in a

follow-up lesson. Actual timings will depend on the needs of your students.

7 0

3 years ago

(10,-3) (3,2) how do i do this

sweet [91]

Answer:

To graph this on a coordinate plane, you have to go left 10 and down to -3. On 3,2, you go right 3 then up 2.

Step-by-step explanation:

6 0

3 years ago

PLZ HELP ME!! THE PICTURE IS BELOW!! NO LINKS!!!

sineoko [7]

<h3>Answer: A) 6.4</h3>

==========================================================

Explanation:

Refer to the diagram below. I've added the points A, B, C, D, and E. Point A is the center of the circle while points B, C and D are along the circle's edge. The radius AC and chord BD intersect at point E.

Recall that whenever we have a radius perpendicular to a chord like this, it means that the radius bisects the chord. So that means chord BD is cut into two equal pieces BE and ED. The diagram given to you tells us that ED = x, so BE is also x units long as well. Overall, BD = BE+ED = x+x = 2x units.

Since BE = ED, the arcs formed are congruent as well. Minor arc BC is the same measure as minor arc CD. Both are 45 degrees. They combine to 90 degrees. In turn, this leads to central angle DAB to be 90 degrees.

Note how triangle DAB is an isosceles right triangle. The two equal legs are the two radii AB and AD, both which are 9 units long. The hypotenuse BD is equal to sqrt(2) times the leg length, so BD = 9*sqrt(2) units long.

Earlier I mentioned that BD = 2x also. We'll equate the two right hand side expressions and solve for x like so:

2x = 9*sqrt(2)

x = (9*sqrt(2))/2

x = (9/2)*sqrt(2)

x = 4.5*sqrt(2)

x = 6.36396103067892

That value is approximate. Rounding to the nearest tenth leads to the final answer of 6.4; therefore, the answer is choice A.

8 0

3 years ago

Please help convert .. 1 yard of sand weights 1.13 tons , I paid $45.79 per ton what do I charge for a yard ?

saw5 [17]

The definite answer is 51.7427

5 0

4 years ago

A sample of 18 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n

ki77a [65]

Answer:

i. x=- - - - - -

ii. o=- - - - - -

iii. Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.

c) The statistics variable X is a measure on a sample that is used as an estimate of the population mean.X is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters because the population standard deviation is known.

N(X, o/ $\sqrt{n}$ )

So, the distribution is

N(2, 0.12/ $\sqrt{16}$ )

i. The 90% confidence interval for the population mean weight of the candies is 1.9589 , 2.0411

iii. The error bound is 0.0411

i. The 98% confidence interval for the population mean weight of the candies is 1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

Step-by-step explanation:

i. x=- - - - - -

ii. o=- - - - - -

iii. Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.

c) The statistics variable X is a measure on a sample that is used as an estimate of the population mean.X is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters because the population standard deviation is known.

N(X, o/ $\sqrt{n}$ )

So, the distribution is

N(2, 0.12/ $\sqrt{16}$ )

i. The 90% confidence interval for the population mean weight of the candies is 1.9589 , 2.0411

iii. The error bound is 0.0411

i. The 98% confidence interval for the population mean weight of the candies is 1.9418 , 2.0582

iii. The error bound is 0.0582

Hence the interval in part is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

5 0

3 years ago