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3 years ago

14

What is the volume of a cube with side 12m?

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

1728 m^3.

Step-by-step explanation:

As all the sides of a cube are , by definition, equal the answer is 12^3

= 1728 m^3.

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Rectangle ABCD is shown to the right. Point E is located

mafiozo [28]

A) The area of the rectangle ABCD is base times height. 20in x 12in = 240 in sq.
B) The area of the triangle AED is base times height divided by two. (14in x 12in)/2 = 84in sq.
C) Figure EBCD is a right trapezoid (having one pair of parallel sides, while the others are slanted and forming a right angle).
D) Area of EBCD is the area of the rectangle minus the area of the triangle. 240in sq - 84in sq = 156in sq.

4 0

2 years ago

Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.

Blizzard [7]

Answer:

The answer is

$y = 3$

$y = - 4$

Step-by-step explanation:

We must find a solution where

$\frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

$\frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1}$

Which equals

$\frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)}$

Add the fractions

$\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Simplify the right side by multiplying the fraction

$\frac{6y}{(y + 1)(y + 2)}$

Set both fractions equal to each other

$\frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}$

Since the denomiator are equal, we must set the numerator equal to each other

$6y = {y}^{2} + 7y - 12$

$= {y}^{2} + y - 12$

$(y + 4)(y - 3)$

$y = - 4$

$y = 3$

6 0

3 years ago

Read 2 more answers

If KL = LM and KJ = JM, find m ∠KJL<br><br> please, i really need your help!

umka2103 [35]

The triangles are congruent by SAS, so the two angles with 7x and 3x+16 are equal. So

7x=3x+16
4x=16
x=4

So KJL=7(4)=28.

3 0

3 years ago

A right triangle has side lengths 4 units, 5 units, and x units what is the difference between the difference values of x?

irina [24]

Use the Pythagorean theorem.

If x is a hypotenuse, then we have:

$x^2=4^2+5^2\\\\x^2=16+25\\\\x^2=41\to x=\sqrt{41}$

If x is a leg, then we have:

$x^2+4^2=5^2\\\\x^2+16=25\ \ \ \ |-16\\\\x^2=9\to x=\sqrt9\to x=3$

Answer: $\sqrt{41}-3$

6 0

3 years ago

NEED HELP NOW!!!!!!!

anzhelika [568]

Step-by-step explanation:

the area of a triangle is

baseline × height / 2

the baseline (where the height hits at a 90° angle) is 4 m.

the height is 3.7 m.

so, the area is

4 × 3.7 / 2 = 2 × 3.7 = 7.4 m²

4 0

2 years ago