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Assoli18 [71]
2 years ago
9

Help me im tired of posting

Mathematics
2 answers:
yaroslaw [1]2 years ago
8 0

Stop posting this. It's very rude to continue posting this. One post was enough.

drek231 [11]2 years ago
7 0
Maybe if you put more points people would actually answer, stop posting again and again
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Complete the square to find the minimum value of the expression 4x2 + 8x + 23.
Tcecarenko [31]
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19

I'm going to assume the given equation equals zero..

So, If we add subtract 19 from both sides of the equation we get the perfect square.

4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0

for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)

Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.


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makvit [3.9K]
The answer is 3 hope this helps
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Simply the expression below <br><br> (10-3i)(2-5i)
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An arc on a circle measures 295°. The measure of the central angle, in radians, is within which range? 0 to StartFraction pi Ove
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