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Helga [31]
3 years ago
12

Pls help I will fail 10th grade

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

B) -6

Step-by-step explanation:

Placing a minus sign outside absolute value bars gives you a negative result For example, –|6| = –6, and –|–6| = –6.

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If f(x) =4x^2 and g(x) =x+1, find (f*g) (x)
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(f * g)(x) = 4x^2(x + 1)
                  4x^3 + 4x^2
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Kevin needs to run 320 meters a day for his training program. He plans on running around the high school track shown. If he runs
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No, he will still need to run 50 more meters. (A)

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Plrase help ya'll I am going to rip my hair out i'm overthinking
vesna_86 [32]

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add the 2 lengths of the given parts.

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3. (6 Points). Solve the initial value problem y'-y.cosx=0, y(pi/2)=2e
Stells [14]

Answer:

y=2e^{sin(x)}

Step-by-step explanation:

Given equation can be  re written as

\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating  \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c............(i)

Now it is given that y(π/2) = 2e

Applying value in (i) we get

ln(2e) = sin(π/2) + c

=> ln(2) + ln(e) = 1+c

=> ln(2) + 1 = 1 + c

=> c = ln(2)

Thus equation (i) becomes

ln(y) = sin(x) + ln(2)

ln(y) - ln(2) = sin(x)

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y= 2e^{sinx}

7 0
3 years ago
I’m having a hard time understanding substitution. Please help!
Vikentia [17]

b_1=\frac{2A}{h}-b_2

Step-by-step explanation:

Given expression is;

A=\frac{h(b_1+b_2)}{2}

Solving for b_1

Multiplying both sides by 2

2*A=\frac{h(b_1+b_2)}{2}*2\\2A=h(b_1+b_2)

Dividing both sides by h

\frac{2A}{h}=\frac{h(b_1+b_2)}{h}\\\frac{2A}{h}=b_1+b_2

Subtracting b_2 from both sides

\frac{2A}{h}-b_2=b_1+b_2-b_2\\\frac{2A}{h}-b_2=b_1\\b_1=\frac{2A}{h}-b_2

b_1=\frac{2A}{h}-b_2

Keywords: division, subtraction

Learn more about subtraction at:

  • brainly.com/question/11145277
  • brainly.com/question/11150876

#LearnwithBrainly

3 0
3 years ago
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