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Novay_Z [31]
3 years ago
11

What is the equation of the line that contains the point 46x30 and has a slope of -3?

Mathematics
1 answer:
BARSIC [14]3 years ago
6 0

Answer:

y=-3x+30

Step-by-step explanation:

Written in: y=mx+b

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Segment Segment X Y is dilated through point M with a scale factor of 2. Which segment shows the correct result of the dilation?
olga nikolaevna [1]

Answer:

just add

Step-by-step explanation:

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2 years ago
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What does the “equity” of a tax mean?
Doss [256]

Answer:

Equity of taxation means each citizen pays an amount of tax equal to their income and ability to pay the tax.

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2 years ago
Find the value of x when 6-4x = 6x-8x-2.
mestny [16]

Answer:

4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6−4x=6x−8x−2

6+−4x=6x+−8x+−2

−4x+6=(6x+−8x)+(−2)(Combine Like Terms)

−4x+6=−2x+−2

−4x+6=−2x−2

Step 2: Add 2x to both sides.

−4x+6+2x=−2x−2+2x

−2x+6=−2

Step 3: Subtract 6 from both sides.

−2x+6−6=−2−6

−2x=−8

Step 4: Divide both sides by -2.

−2x−2=−8−2

x=4

here is a link:

https://www.mathpapa.com/algebra-calculator.html?q=6-4x%3D6x-8x-2.

6 0
3 years ago
The perimeter of the scalene triangle is 54.6 cm. Which equation can be used to find the value of b if side a measures 8.7 cm?
77julia77 [94]

A scalene triangle is a triangle that has 3 sides that are all different lengths.

Let these letters represent the problem:

a = 8.7

b = side 2

c = side 3

P = 54.6

To find the perimeter, we just need to add all the sides [ P = a + b + c ]

So, put what we have in the formula above.

54.6 = 8.7 + b + c

Best of Luck!

7 0
3 years ago
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Find the point on the parabola y^2 = 4x that is closest to the point (2, 8).
guapka [62]

Answer:

(4, 4)

Step-by-step explanation:

There are a couple of ways to go at this:

  1. Write an expression for the distance from a point on the parabola to the given point, then differentiate that and set the derivative to zero.
  2. Find the equation of a normal line to the parabola that goes through the given point.

1. The distance formula tells us for some point (x, y) on the parabola, the distance d satisfies ...

... d² = (x -2)² +(y -8)² . . . . . . . the y in this equation is a function of x

Differentiating with respect to x and setting dd/dx=0, we have ...

... 2d(dd/dx) = 0 = 2(x -2) +2(y -8)(dy/dx)

We can factor 2 from this to get

... 0 = x -2 +(y -8)(dy/dx)

Differentiating the parabola's equation, we find ...

... 2y(dy/dx) = 4

... dy/dx = 2/y

Substituting for x (=y²/4) and dy/dx into our derivative equation above, we get

... 0 = y²/4 -2 +(y -8)(2/y) = y²/4 -16/y

... 64 = y³ . . . . . . multiply by 4y, add 64

... 4 = y . . . . . . . . cube root

... y²/4 = 16/4 = x = 4

_____

2. The derivative above tells us the slope at point (x, y) on the parabola is ...

... dy/dx = 2/y

Then the slope of the normal line at that point is ...

... -1/(dy/dx) = -y/2

The normal line through the point (2, 8) will have equation (in point-slope form) ...

... y - 8 = (-y/2)(x -2)

Substituting for x using the equation of the parabola, we get

... y - 8 = (-y/2)(y²/4 -2)

Multiplying by 8 gives ...

... 8y -64 = -y³ +8y

... y³ = 64 . . . . subtract 8y, multiply by -1

... y = 4 . . . . . . cube root

... x = y²/4 = 4

The point on the parabola that is closest to the point (2, 8) is (4, 4).

4 0
2 years ago
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