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Anika [276]
2 years ago
5

What is the Volume of the Sphere? ​

Mathematics
1 answer:
IgorLugansk [536]2 years ago
7 0

Answer:

7776\pi

Step-by-step explanation:

Sphere Volume Formula = 4/3 times \pi times r^2

r is the radius and in this case its 18.

4/3 times \pi times 18^3

4/3 times 5832 times \pi

4 times 1944 times \pi

7776 times \pi

The volume of the sphere is 7776\pi

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A baseball camp is held at a complex that has 6 baseball diamonds. The coaches would like each diamond to have the same number o
Artyom0805 [142]

Answer:

Using divisibility rules, it is impossible to have exactly the same number of kids in each of the diamonds

Step-by-step explanation:

Here, we want to use divisibility rule to check for the possibility of 152 kids showing for the kids

Since we need exactly equal number of kids in each of the diamonds, we are going to test the possibilities that we can share 152 to have the same number of campers in each of the diamond

Mathematically 152/6 = 25.3333

Since we have a remainder for the division, it is impossible to share the campers equally in the six diamonds if 152 kids show up for the camp

4 0
3 years ago
The box at the right is a cube with edges that measure 2 feet. The sides of the triangle inside the cube are a diagonal of a fac
zvonat [6]

Answer:

Area = 2 \sqrt{2}

Step-by-step explanation:

Given

Length_1 = 2

Length_2 = \sqrt{2^3}

Required

Determine the area of the triangle

The given lengths represent the height and base length of the triangle.

So, the area is;

Area = \frac{1}{2} * Length_1 * Length_2

Substitute values for Length1 and Length2

Area = \frac{1}{2} * 2 * \sqrt{2^3}

Area = \frac{2}{2} * \sqrt{2^3}

Area = 1* \sqrt{2^3}

Area = \sqrt{2^3}

Express 2^3 as 2 * 2 * 2

Area = \sqrt{2*2*2}

Area = \sqrt{4*2}

Split

Area = \sqrt{4} *\sqrt{2}

Area = 2 *\sqrt{2}

Area = 2 \sqrt{2}

6 0
3 years ago
What expression is equivalent to 3/5
Mkey [24]

Answer:

6/10 is equivalent to 3/5, so is 9/15.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Graphs can be used to estimate information not represented on the graph. True or False
Verizon [17]
I believe that it is true.
5 0
3 years ago
Read 2 more answers
Please help me i dont understand
Eva8 [605]

Answer:15*(x-3)^2*(x-5)

Step-by-step explanation:

\dfrac{x^2-y^2}{x^2-8x+15}\ and\ \dfrac{y^2}{15(x^2-6x+9)} \\\\\\x^2-8x+15=x^2-3x-5x+15=x(x-3)-5(x-3)=(x-3)(x-5)\\\\15(x^2-6x+9)=15*(x-3)^2\\\\LCM (x^2-8x+15,15(x^2-6x+9)\\\\=LCM((x-3)(x-5),15(x-3)^2)\\\\\boxed{=15*(x-3)^2*(x-5)}\\

8 0
3 years ago
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