There is 6 people in the van that isn't full. I am counting. They are counting students. They are going to group them in 2 vans of 11 people and 1 van of 6 people.
Wouldn’t you have to divide or subtract the acute degree with 105 and 30?
Answer:
15 & 7
Step-by-step explanation:
f - s = 8
f = 8 + s
Twice the first number plus three times the second number is 51:
2f + 3s = 51
Substitute:
2(8 + s) + 3s = 51
16 + 2s + 3s = 51
16 + 5s = 51
5s = 51 - 16
5s = 35
s = 7, the second number
Find f:
f = 8 + 7 = 15, the first number
f - s = 8
15 - 7 = 8
8 = 8
Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
Answer:
mark brainliest :))
Step-by-step explanation:
In a box and whisker plot: the ends of the box are the upper and lower quartiles, so the box spans the interquartile range. the median is marked by a vertical line inside the box. the whiskers are the two lines outside the box that extend to the highest and lowest observations.
