Answer:
this is the answer for 4th question
and it is a collinear
#1: 0.3404255319
#2: 5.2 repeat
#3: 6.714285714
#4: 9.4
#5: 15.6 repeat
#6: 23.5 repeat
I am not 1,000 percent sure that this is right. If it is not then please tell me! Hope this helped if it was correct!
D. QR and CD
I hope this helps. :)
74,000 / 500 = 148 months or 12 years and 4 months
Answer:
C.5
Step-by-step explanation:
Fiona:
After t trials, she would have:
![f(t) = 4.127(1.468)^t](https://tex.z-dn.net/?f=f%28t%29%20%3D%204.127%281.468%29%5Et)
Karl:
After t trials, he would have:
![k(t) = 0.897(1.992)^t](https://tex.z-dn.net/?f=k%28t%29%20%3D%200.897%281.992%29%5Et)
At what number of trials would Fiona and Karl have the same number of beans?
This is t for which:
![f(t) = k(t)](https://tex.z-dn.net/?f=f%28t%29%20%3D%20k%28t%29)
So
![4.127(1.468)^t = 0.897(1.992)^t](https://tex.z-dn.net/?f=4.127%281.468%29%5Et%20%3D%200.897%281.992%29%5Et)
![0.897(1.992)^t = 4.127(1.468)^t](https://tex.z-dn.net/?f=0.897%281.992%29%5Et%20%3D%204.127%281.468%29%5Et)
![\frac{(1.992)^t}{(1.468)^t} = \frac{4.127}{0.897}](https://tex.z-dn.net/?f=%5Cfrac%7B%281.992%29%5Et%7D%7B%281.468%29%5Et%7D%20%3D%20%5Cfrac%7B4.127%7D%7B0.897%7D)
![(\frac{1.992}{1.468})^t = 4.6](https://tex.z-dn.net/?f=%28%5Cfrac%7B1.992%7D%7B1.468%7D%29%5Et%20%3D%204.6)
![(1.35695)^t = 4.6](https://tex.z-dn.net/?f=%281.35695%29%5Et%20%3D%204.6)
![\log{(1.35695)^t} = \log{4.6}](https://tex.z-dn.net/?f=%5Clog%7B%281.35695%29%5Et%7D%20%3D%20%5Clog%7B4.6%7D)
![t\log{1.35695} = \log{4.6}](https://tex.z-dn.net/?f=t%5Clog%7B1.35695%7D%20%3D%20%5Clog%7B4.6%7D)
![t = \frac{\log{4.6}}{\log{1.35695}}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog%7B4.6%7D%7D%7B%5Clog%7B1.35695%7D%7D)
![t = 5](https://tex.z-dn.net/?f=t%20%3D%205)
So the correct answer is 5 trials, option C.