What is the domain of the function on the graph?

Sofia cuts a piece of felt in the shape of a kite for an art project. The top two sides measure 20 cm each and the bottom two si

Phantasy [73]

x + y = 24 where x and y are the 2 parts of diagonal Other diagonal wil be smaller that 24.
x^2 + z^2 = 13^2
y^2 + z^2 = 20^2 where z = 0.5 * length of smaller diagonal)

form last 2 equations

y^2 - x^2 = 20^2 - 13^2 = 231
now y = 24-x so we have

(24 - x)^2 - x^2 = 231

576 - 48x = 231

48x = 345

x = 7.1875

z^2 = 13^2 - 7.1875^2 = 117.34
z = 1.83

so smaller diagonal = 21.66 cm

looks like its the third choice.

5 0

3 years ago

Evaluate the expression for k = 2. –9 + 7k =

zhannawk [14.2K]

Answer:

k = 7/6

Step-by-step explanation:

8 0

3 years ago

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning ca

Fed [463]

Answer:

Sam had a finish time with a z-score of -2.93.

Karen had a finish time with a z-score -1.91.

Sam had the more convincing victory.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sam:

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning car, driven by Sam, finished in 185.85 minutes.

So $\mu = 186.94, \mu = 0.372, X = 185.85$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{185.85 - 186.94}{0.372}$

$Z = -2.93$

Sam finishing time was 2.93 standard deviations below the mean.

Sam had a finish time with a z-score of -2.93.

Karen:

The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

So $\mu = 110.7, \sigma = 0.115, X = 110.48$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110.48 - 110.7}{0.115}$

$Z = -1.91$

Karen finishing time was 1.91 standard deviations below the mean.

Karen had a finish time with a z-score -1.91.

Who had the more convincing victory?

Sam finishing time was 2.93 standard deviations below the mean.

Karen finishing time was 1.91 standard deviations below the mean.

Sam finished more standard deviations below the mean than Karen, that is, he was faster relative to his competition than Karen.

So Sam had the more convincing victory.

8 0

3 years ago

Can u help me solve for this question please

Ymorist [56]

Answer:

48?

Step-by-step explanation:

If x = 30 and y = 36

(Instead of 6 add 8 to 40 to be proportional

7 0

3 years ago

Evaluate 6x - 3, when x = 2 14

Rudiy27

Answer:

6x214=1284

1284-3 is 1281

Step-by-step explanation:

7 0

3 years ago