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3 years ago

An example of dependent events is drawing a blue marble out of one jar and then drawing a

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

Answer:

A red marble out of the same jar, without replacing the first marble.

Step-by-step explanation:

Dependent events are those which involve a first event which affects the outcome of the second event.

This means that the probability of the second event changes because of the occurrence of the first event.

So if a blue marble is drawn out of one jar, then drawing a red marble out of the same jar, without replacing the first marble would be an example of dependent events.

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A credit card customer owes $325.60 they charge another purchase of $45.20. how much money does the customer owe?

Burka [1]

$367.80 because you have to add up the purchase the owe and the other one too, then you get your answer

8 0

2 years ago

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Please do number 3___________________

Alexandra [31]

9514 1404 393

Answer:

m∠SVW = 80°

Step-by-step explanation:

3. The sum of same-side interior angles SVW (4x°) and VWT (5x°) is 180°. This can be used to solve for x and to find the angle values.

4x + 5x = 180

9x = 180 . . . . . . . . collect terms

x = 20 . . . . . . . . . . divide by 9

m∠SVW = 4x° = 4(20)°

m∠SVW = 80°

_____

4. Then m∠VWT = 180° -80° = 100° = 5x°.

5. Consecutive interior angles are supplementary. ("Same-side" and "consecutive" are used interchangeably in this context.)

4 0

3 years ago

Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.

borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 14, p = 0.8$

P(x>10)

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501$

$P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501$

$P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539$

$P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440$

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981$

So P(x > 10) = 0.6981.

8 0

2 years ago

X/5 (fraction) (10 - 11) = 2 Solve for X

vekshin1

x/5(10-11) Remember PEMDAS and remember to isolate the variable;)

1. x/5(10-11) =2 (subtract)

2. x/5 * -1 =2 (add +1 to each side)

3. x/5= 3 (multiply both sides by five)

4. x=15

5 0

2 years ago

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Create a scenario that would fit the given expression. 5x

densk [106]

Answer:

You have 5 marbles and your friend has 30 marbles. How many times more marbles does your friend have? Write an equation using the variable x to solve the problem.

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2 years ago