All categories

2 years ago

Which equation matches this graph?

Mathematics

1 answer:

Harman [31]2 years ago

6 0

Answer:

y = 4"x +2

Step-by-step explanation:

We choose negative 4 because the graph lies below the asymptote and we chose positive 2 because the horizontal asymptote is on the positive section of the y axis

You might be interested in

A triangle has sides 12cm, 9cm and 15cm. Is the triangle right-angled? Justify your answer

marusya05 [52]

Answer:

yes

Step-by-step explanation:

Yes this triangle is right angled and can be justified using the Pythagorean theorem. The theorem states that: $a^{2} +b^{2} = c^{2}$ . Substitute using the given values:

(9^2)+(12^2)=15^2

81 + 144 = 255

255 = 255.

It satisfies the theorem therefore it is a right angle triangle.

3 0

3 years ago

Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP

Wittaler [7]

Answer:

$\frac{41}{3} < 14 < \sqrt{200}$

<u> $0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} }$ </u>

Step-by-step explanation:

$\sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6$

So ;

$\frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1$

$\frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6$

So ;

$0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75$

I hope I helped you^_^

6 0

2 years ago

Find cos(B) A.) 7/3 B.) 3/7 C.) 3/58 D.) 7/58

Alex Ar [27]

A. 7/3
HOPE IT HELLS U!!!!

7 0

3 years ago

Round 1.0649 to the nearest thousandth.

yuradex [85]

1.065. The 5 is the nearest thousandth

5 0

3 years ago

Read 2 more answers

The function h(x) is defined as shown.

pav-90 [236]

1. For x<3, h(x)=x+2

now x+2 is an increasing line (a practical way to check, h(1)=3, h(2)=4)

the largest value it takes is at 3, not inclusive, so h(3)=5 not inclusive.

Range_1= (-∞, 5)

2. for x> or equal to 3, h(x)=-x+8, which is a decreasing line (check h(4)=4, h(5)=3 )

so this line takes its maximal value at x=3, f(3)=5 and then takes any other value to -∞.

Range_2=(-∞,5]

3. Range(h)=Range1∪Range2=(-∞, 5)∪(-∞,5]=(-∞,5] (B)

6 0

3 years ago

Read 2 more answers