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1 year ago

Help please anyone please

Mathematics

1 answer:

Brilliant_brown [7]1 year ago

5 0

Answer:

You seem to have two questions, so I will answer both!

Step-by-step explanation:

The answer for the cube volume is D

If you remove a cube from another cube it is affecting more than one side, hence the -1 on two differents p's.

The true area of that house is 48m^2

Take the before scaling it, multiply it by the scale (200)

Square your answer and get around 48 m^2

(You actually get like 48.9897 etc, but we are kind of ignoring that)

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M is the midpoint of , cm = 2x + 3, and md = 3x – 6. what is cd? answer

wlad13 [49]

<span>If M is the midpoint of CD, CM = 2x+3 and MD = 3x-6, then:

MD = CM
3x - 6 = </span>2x + 3
3x - 2x = 3 + 6
x = 9

CM = 2x+3 = 2*9+3 18+3 = 21
MD = CM = 21
CD = CM + MD = 21 + 21 = 42

7 0

3 years ago

WILL MARK BRAINLIEST!!!

Rus_ich [418]

Answer:

y= -2x -4

Step-by-step explanation:

slope: rise/run = 2/-1 = -2

y-intercept: -4

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2 years ago

Ms. Ross has 24 students. 2/3 of her students have brown hair. The rest have blonde. How many students have brown?

Dimas [21]

The answer would be 16 because 24 divided by 3 is 8. 8 multiplied by 2 is 16. 16 students have brown hair.

3 0

3 years ago

Read 2 more answers

Can someone help me please

fredd [130]

The answer to that is C.

6 0

3 years ago

When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will

PtichkaEL [24]

Answer:

The correct answer is 9 m per $second^{2}$

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per $second^{2}$

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x m per $second^{2}$ .

∴ 54 = m × x

⇒ x = $\frac{54}{6}$ = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per $second^{2}$ .

6 0

3 years ago