Question

2x squared plus 16x minus 10 equals 0. please solve for the solution

Answer 1

Answer: 5/9

Solution: 2x^2+16x-10=0

According to formula: X=(-16+_sqrt(16^2-(-10•2)) / 2•2

X=5/9

Answer 2

Answer:

x = 0.58 or x = -8.58 to 2 d.p.

Step-by-step explanation:

Question:

Just to write the question in a better format :

$2x^{2} +16x-10 = 0$

Solve for x.

Answer:

First we Simplify this by dividing everything by 2:  

$2x^{2} +16x-10 = 0$ ÷ 2 :

$x^{2} +8x-5 = 0$

Now we use the quadratic formula :

$x = \frac{-b+/-\sqrt{b^{2} -4ac} }{2a}$  (side note: +/- is meant to be ±)

Now we substitute a with 1, b with +8 and c with -5:

$x = \frac{-8+/-\sqrt{8^{2} -4(1)(-5)} }{2(1)}$  $x = \frac{-8+/-\sqrt{64+20} }{2}$ $x = \frac{-8+/-\sqrt{84} }{2}$  

The surd $\sqrt{84}$ = 2$\sqrt{21}$ So :

x = -8± 2√21 /2

x = -4 ±√21

This is our answer . Remember it is two answers in 1.

x = -4 +√21 and x = -4 -√21

x = 0.58257569495  or x = -8.58257569496

x = 0.58 or x = -8.58 to 2 d.p.

Hope this helped and brainliest please