Answer:
11.1 units
Step-by-step explanation:
We solve for this using the formula when using coordinates (x1 , y1) and (x2, y2)
= √(x2 - x1)² + (y2 - y1)²
A(5,2), B(5,4), and C(1,1).
For AB = √(x2 - x1)² + (y2 - y1)²
= A(5,2), B(5,4)
= √(5 - 5)² +(4 - 2)²
= √ 0² + 2²
= √4
= 2 units
For BC = √(x2 - x1)² + (y2 - y1)²
= B(5,4), C(1,1)
= √(1 - 5)² +(1 - 4)²
= √ -4² + -3²
= √16 + 9
= √25
= 5 units
For AC = √(x2 - x1)² + (y2 - y1)²
A(5,2), C(1,1)
= √(1 - 5)² + (1 - 2)²
= √-4² + -1²
= √16 + 1
= √17
= 4.1231056256 units
The Formula for the Perimeter of Triangle = Side AB + Side BC + Side AC
= 2 units + 5 units + 4.1231056256 units
= 11.1231056256 units.
Approximately the Perimeter of a Triangle to the nearest tenth = 11.1units
Answer:
20, 4
Step-by-step explanation:
Let's assume total number of students registered is n
Last week n/4 people are absent
so people present are n - n/4 = <u>3n/4</u>
Today after return of Jen 1/5 n are absent
so people present are n - n/5 = 4n/5
which is also equal to last week present people + 1 (Jen)
= 3n/4 + 1
= (3n + 4) / 4
so (3n + 4) / 4 = 4n/5
=> 3n + 4 = 4n/5 * 4
=> (3n + 4) * 5 = 16n
=> 15n + 20 = 16n
=> 20 = n
=> n = 20
So total students registered for class is 20
today no of people absent = n/5 = 20/5 = 4
Answer:
g(q) = 5/8q
Step-by-step explanation:
-7q + 12r = 3q - 4r
Add 4r to each side
-7q + 12r+4r = 3q - 4r+4r
-7q +16r = 3q
Add 7q to each side
-7q+7q +16r = 3q+7q
16r = 10q
Divide each side by 16
16r/16 = 10q/16
r = 5q/8
g(q) = 5/8q
The "midpoint formula" is the same as the "average formula:"
x-coordinate of the midpoint = average of -2 and 10:
= (-2 + 10) / 2 = 4
y-coordinate of the midpoint = average of 3 and 3:
= (3+3) / 2 = 3
Thus, the midpoint of the given line segment is (4,3).
Answer: 
Step-by-step explanation:
Given
Length of rectangle is 
Perimeter must be greater than 40 ft
Suppose l and w be the length and width of the rectangle
So, the smallest width can be
