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2 years ago

Help pwease with a cherry on top

Mathematics

2 answers:

Contact [7]2 years ago

7 0

I’m with the other person

Sophie [7]2 years ago

3 0

Answer:

I think it's D sorry if I get it wrong

Step-by-step explanation:

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Mike's grandmother opened a savings account in Mike's name and deposited some money into the account. The account pays an annual

Snowcat [4.5K]

SI = prt/100
1440 = (p*9*8)/100
⇒p=2000

7 0

3 years ago

HELP PLEASEEEEEEEEEEEEEEEEEEEEE

Over [174]

Answer:

15.25×3

45.75-5

=40.75

3 0

3 years ago

I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr

Illusion [34]

Answer:

<h2><u>question 1</u></h2>

$n^{2} - 20n -96 = 0$

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

in the form $ax^{2} +bx +c = 0$

= $x^{2} +12x - 48$

make use of the formula :

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

replace values to make 2 equations :

1. $\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1}$ = 3.17

2. $\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1}$ = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

in the form $ax^{2} +bx +c = 0$

this becomes $5b^{2} -20b-18-7$

= $5b^{2} -20b-25$

can simplify by 5

= $b^{2} -4b-5 =0\\$

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0

3 years ago

Read 2 more answers

F(x) = 5x<br> G(x) = 3x + 5

Alja [10]

Answer:

f(g(x)) = 5(3x + 5) = 15x + 25

g(f(x)) = 3(5x) + 5 = 15x + 5

Step-by-step explanation:

Since you didn't say what you were trying to find, I'll give you a couple things you may have been trying to find.

f(g(x)) = 5(3x + 5) = 15x + 25

g(f(x)) = 3(5x) + 5 = 15x + 5

3 0

2 years ago

oyce is trying to solve the equation y = x2 − 8x + 7 using the quadratic formula. She has made an error in one of the steps belo

Naddik [55]

You didn't attach anything, but this is how you should solve this equation: given an equation $ax^2+bx+c=0$ the solutions are

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In your case, the values are $a=1,\ b=-8,\ c=7$ . If you plug these values inside the solving formula, you have

$x_{1,2} = \dfrac{8\pm\sqrt{64-4\cdot 1\cdot 7}}{2\cdot 1} = \dfrac{8\pm\sqrt{64-28}}{2} = \dfrac{8\pm\sqrt{36}}{2} = \dfrac{8\pm6}{2} = 4\pm3$

So, the two solutions are 1 and 7

3 0

3 years ago