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kkurt [141]
2 years ago
15

Translate and solve: The difference of n and 1/6 is 1/2.

Mathematics
1 answer:
enyata [817]2 years ago
4 0
<h2>Translating Words into Problems</h2>

We can translate a word equation into a mathematical equation by translating key words into operations.

  • <em>difference</em> = subtract
  • <em>is</em> = equals

<h2>Addinng Fractions</h2>

Whenever we need to add one fraction to another, we must find a common denominator, change both the fractions for their denominators to be the same, and then add the numerators. Finally, we reduce the fraction.

<h2>Solving the Question</h2>

We're given:

  • The difference of n and \dfrac{1}{6} is \dfrac{1}{2}.

Translate the given information into an equation:

⇒ n-\dfrac{1}{6}=\dfrac{1}{2}

Solve for <em>n</em>:

⇒ n-\dfrac{1}{6}=\dfrac{1}{2}\\\\n=\dfrac{1}{2}+\dfrac{1}{6}\\\\n=\dfrac{3}{6}+\dfrac{1}{6}\\\\n=\dfrac{4}{6}\\\\n=\dfrac{2}{3}

<h2>Answer</h2>

n=\dfrac{2}{3}

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Answer:

3 1/2

Step-by-step explanation:

You have to do 7 divided by 2 or 1/2 x 7

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3 years ago
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An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th
Irina-Kira [14]
Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is \sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by 8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h

Area of the four side faces of the aquarium is 4 times the length of the base times the height = 4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}

Total area to be covered by grass is the base and the four side faces and is given by \frac{20}{h}+\sqrt{320h}

Cost of the entire metal frame = 7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h

Cost of the entire grass = 8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h

Therefore, total cost in terms of the height, h, is given by

C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h
3 0
3 years ago
2 questions here:
solmaris [256]
<span>1. Make y the subject 
a) 4y=12x+18
y = 3x + 4.5

b) 2x=7-3y
3y = -2x + 7
y = -2/3x + 7/3

2.
a) what is the equation of the line which passes through both (-2,-4) and (6,16)

slope = (16 + 4)/(6 +2) = 20/8 = 2.5
y = mx + b
-4 =2.5(-2) +b
-4 = -5 +b
b = 1

equation
y = 2.5x + 1


b) what is the equation of the line perpendicular to y= 1/2X + 7 passing through point (3,9)

</span>y= 1/2X + 7
slope = 1/2

slope of line perpendicular = -2

passing through point (3,9)

y = mx + b
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equation

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6 0
3 years ago
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dybincka [34]
<h3>:- Solution</h3>

-8x - 9 > -21

Move -9 to right side

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the answer to -8x - 9 > -21 is <u>x</u><u> </u><u><</u><u> </u><u>3</u><u>/</u><u>2</u>

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Answer:

B

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r = a + b cos(theta)

1 < a/b < 2

In B, a/b is 3/2

Which is between 1 and 2

7 0
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