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3 years ago

If trstan has a pickup truck that could carry 7/4 cord of firewood, FInd the number trips needed to cary 63 cords of wood

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Answer:

Step-by-step explanation:

63/(7/4) 63 divided by 7/4

63* 4/7 63 multiplied by 4/7

=36 answer is 36

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Taseem’s loose change consists of dimes and quarters. When you ask her how many of each type of coin she has, she gives you the

sweet-ann [11.9K]

The statement first, and the statement second are correct because the number of dimes is 34, and the number of quarters is 66

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have:

0.1x + 0.25y = 19.9 and

x + y = 100

Let x = number of dimes

y = number of quarters

After solving the above system of equations by substitution method.

$\rm \dfrac{398-5y}{2}+y=100$

y = 66

$\rm x=\dfrac{398-5\cdot \:66}{2}$

x = 34

Thus, the statement first, and the statement second are correct because the number of dimes is 34, and the number of quarters is 66

Learn more about the linear equation here:

brainly.com/question/11897796

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4 0

2 years ago

The weight of a dog crate is 5.6 lbs. the crate and 3 puppies together weigh 36.35 lbs. estimate the weight of one puppy.

nata0808 [166]

36.35 - 5.6 = 30.75 ÷ 3 = 10.25

7 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

How do I solve this problem

zysi [14]

The following equations are solved in terms of x:
a) 2x - 3 = y
2x = y + 3
x = (1/2)y + 3/2

b) 2 + 2x - 1 = 4y
2x - 1 = 4y
2x = 4y + 1
x = 2y + 1/2

c) 2A + 4x + 3B = 10
4x = 10 - 2A - 3B
x = 5/2 - (1/2)A - (3/4)B

5 0

3 years ago

Please help me solve this problem -5= -32 please and thank you

Ymorist [56]

Answer: false

Step-by-step explanation: Compare -5 and -32. They do not equal each other.

8 0

2 years ago