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OLga [1]
2 years ago
13

Simplify this algebra expression: 6j-2j-2j+8+9+6e+5

Mathematics
2 answers:
ELEN [110]2 years ago
8 0

Answer:

6j-2j-2j+8+9+6e+5

= 6j - 4j + 6e + 24

= 2j + 6e + 24

galina1969 [7]2 years ago
5 0

Answer:

Your answer is 6e + 2j+22

Step-by-step explanation:

6j2j-2j+8+9+6e +5

6j2j-2j+22+ 6e

6j - 2j - 2j + 22 + 6e

2j + 22 + 6e

2j + 22 + 6e

=6e + 2j + 22

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2 years ago
For what value of x is sin x = cos 19°, where 0°< x < 90°? 38°
Digiron [165]
Sin x =cos 19 X =sin^1(cos 19) X=71
6 0
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Dimas [21]

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Step-by-step explanation:

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4 0
3 years ago
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Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
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