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Viktor [21]
2 years ago
15

Jason’s credit card has an apr of 17.02% and a 30-day billling cycle. the following table details jason’s transactions with that

card in the month of june. date amount ($) transaction 6/1 746.28 beginning balance 6/9 140.00 payment 6/15 28.76 payment 6/18 69.49 purchase between the adjusted balance method and the daily balance method, which method of computing jason’s june finance charge will result in a greater finance charge, and how much greater will it be? a. the daily balance method will have a finance charge $1.02 greater than the adjusted balance method. b. the daily balance method will have a finance charge $0.03 greater than the adjusted balance method. c. the adjusted balance method will have a finance charge $2.36 greater than the daily balance method. d. the adjusted balance method will have a finance charge $1.37 greater than the daily balance method.
Mathematics
1 answer:
forsale [732]2 years ago
5 0

The method of computing that would result in a greater finance charge is  a. the daily balance method will have a finance charge $1.02 greater than the adjusted balance method.

<h3>What is the Adjusted Balance Method?</h3>

This refers to the method of accounting that makes use of the owed amount of money at the end of a billing cycle to make its computation on an account after the credits are calculated.

Hence, we can see that when comparing the adjusted balance method to the daily balance method that calculates the interest charges at the end of the day, the daily balance method would have a higher finance charge.

Read more about adjusted balance methods here:

brainly.com/question/1808408

<h3>#SPJ4</h3>

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In a normal distribution, 95% of the data fall within how many standard
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Answer: two standard deviations

Step-by-step explanation:

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Simplified form of 351 + 524 x 72? Pls
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Answer: 63,000

Step-by-step explanation:

351+524= 875

875 * 72= 63,000

4 0
3 years ago
The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.
Tanya [424]

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

<h3>What is mean, median and mode of a data set?</h3>

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

  • The mean is-

\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5

  • The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

  • The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41   41   43   43   45   50   52   53   54   62   63   63   67   75   97  

  • The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

r=97-41\\r=56

  • The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

IQR=63-23\\IQR=20

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

brainly.com/question/14532771

#SPJ1

4 0
1 year ago
Find the value of x in each case. PLEASE SHOW WORK!!!
myrzilka [38]
m\angle BCA=180^o-5x

\angle CAB=\angle ACD\\\\m\angle CAB=33^o

In the triangle ABC:

m\angle ABC+m\angle BCA+m\angle CAB=180^o\\\\2x+180^o-5x+33^o=180^o\\\\-3x+213^o=180^o\ \ \ |-213^o\\\\-3x=-33^o\ \ \ |:(-3)\\\\x=11^o

4 0
3 years ago
Solve this equation q - 17 = 18<br><br> Thanks!
Lisa [10]

Answer:

q =1

Step-by-step explanation:

q=17-18

.•. q=1

pls mark me as a hot boy

8 0
2 years ago
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