3 years ago

Find the value of x in each case. PLEASE SHOW WORK!!!

1 answer:

4 0

$m\angle BCA=180^o-5x$

$\angle CAB=\angle ACD\\\\m\angle CAB=33^o$

In the triangle ABC:

$m\angle ABC+m\angle BCA+m\angle CAB=180^o\\\\2x+180^o-5x+33^o=180^o\\\\-3x+213^o=180^o\ \ \ |-213^o\\\\-3x=-33^o\ \ \ |:(-3)\\\\x=11^o$

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Given the function <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-2x-5" id="TexFormula1" title="f(x)=x^2-2x-5" alt="f(x)=x^2

juin [17]

Answer:

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Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ - 5, 6 ] , then

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Then

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3 years ago

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It should be one more than the power

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4 years ago

Read 2 more answers

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Elan Coil [88]

Answer:

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3 years ago

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alisha [4.7K]

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Step-by-step explanation:

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Dimas [21]

The last one is the correct answer.

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