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Vladimir [108]
3 years ago
12

Find the value of x in each case. PLEASE SHOW WORK!!!

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0
m\angle BCA=180^o-5x

\angle CAB=\angle ACD\\\\m\angle CAB=33^o

In the triangle ABC:

m\angle ABC+m\angle BCA+m\angle CAB=180^o\\\\2x+180^o-5x+33^o=180^o\\\\-3x+213^o=180^o\ \ \ |-213^o\\\\-3x=-33^o\ \ \ |:(-3)\\\\x=11^o

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Question:

What is the area of the sector? Either enter an exact answer in terms of π or use 3.14 and enter your answer as a decimal rounded to the nearest hundredth.

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the values of radius and central angle are not given.

However, I'll answer the question using the attached figure.

From the attached figure, the radius is 3 unit and the central angle is 120 degrees

The area of a sector is calculated as thus;

Area = \frac{\alpha }{360} * \pi r^2

Where \alpha represents the central angle and r represents the radius

By substituting \alpha = 120 and r = 3

Area = \frac{\alpha }{360} * \pi r^2 becomes

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Area = \frac{1}{3} * \pi * 9

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Area = 3\pi square units

Solving further to leave answer as a decimal; we have to substitute 3.14 for \pi

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Area = 3 * 3.14

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Hence, the area of the sector in the attached figure is 3\pi or 9.42 square units

8 0
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Step-by-step explanation:

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