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Vladimir [108]
3 years ago
12

Find the value of x in each case. PLEASE SHOW WORK!!!

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0
m\angle BCA=180^o-5x

\angle CAB=\angle ACD\\\\m\angle CAB=33^o

In the triangle ABC:

m\angle ABC+m\angle BCA+m\angle CAB=180^o\\\\2x+180^o-5x+33^o=180^o\\\\-3x+213^o=180^o\ \ \ |-213^o\\\\-3x=-33^o\ \ \ |:(-3)\\\\x=11^o

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