Question

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.

Answer 1

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

What is mean, median and mode of a data set?

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

• The mean is-

$\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5$

• The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

• The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41   41   43   43   45   50   52   53   54   62   63   63   67   75   97  

• The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

$r=97-41\\r=56$

• The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

$IQR=63-23\\IQR=20$

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

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