Answer:
vertex: (2,-18)
Step-by-step explanation:
y = ax² + bx + c
(-1,0) : a - b + c = 0 ...(1)
(5,0) : 25a +5b +c = 0 ...(2)
(0,-10): 0a + 0b + c = -10 c=-10
(1) x5: 5a - 5b + 5c = 0 ...(3)
(2)+(3): 30a + 6c = 0 30a = -6c = 60 a = 2
(1): 2 - b -10 = 0 b = -8
Equation: y = 2x² - 8x -10 = 2 (x² -4x +4) - 18 = 2(x-2)² -18
equation: y = a(x-h)²+k (h,k): vertex
vertex: (2,-18)
Answer:
Step-by-step explanation:
If we assume that the boys and girls are equally likely, so the probability of having a girl is equal to probability of having a boy = .
Let B = Event of having a boy.
G= Event of having a girl.
Since both events are independent of each other . (Events that do not depends on each other.)
So irrespective of the four baby boy , the probability that the fifth child is a boy =
Therefore , the probability of a couple having a baby boy when their fifth child is born, given that the first four children were all boys=