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rosijanka [135]
3 years ago
13

16. Consider any eight points such that no three are collinear.

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0
Let's assume that a,b&c are in one straight line, so cannot form a triangle with each other. Now, total possible Triangle that can be formed choosing any 3 points without any colinear constraint is 8C3 = 56
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4 years ago
Solve the inequality
Pie

Answer:

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3 years ago
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6 0
3 years ago
Read 2 more answers
2(3/5n +3) - (2/3n-1)
borishaifa [10]

Hey there! :)


2(3/5n + 3) - (2/3n - 1)


Simplify.


(2 * 3/5n) + (2 * 3) - (2/3n -1)


Simplify.


6/5n + 6 - 2/3n + 1


Add like terms.


(6/5n - 2/3n) + (6 + 1)


Make the fractions have the same denominator by multiplying fraction 1 (6/5n) by 3/3 and fraction 2 (-2/3n) by 5/5.


6/5n * 3/3 = 18/15n


-2/3n * 5/5 = -10/15n


So, our new equation looks like this : (18/15n - 10/15n) + (6 + 1)


Simplify.


8/15n + 6 —> final answer.


Hope this helped! :)

4 0
3 years ago
Read 2 more answers
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