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2 years ago

16. Consider any eight points such that no three are collinear.

1 answer:

8 0

Let's assume that a,b&c are in one straight line, so cannot form a triangle with each other. Now, total possible Triangle that can be formed choosing any 3 points without any colinear constraint is 8C3 = 56

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Triangle ABC was dilated by 50%. What is the relationship between AC and A'C'?

Elina [12.6K]

Answer:

The length of segment AC is two times the length of segment A'C'

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

z ----> the scale factor

A'C' ----> the length of segment A'C'

AC ----> the length of segment AC

$z=\frac{A'C'}{AC}$

we have that

$z=50\%=50/100=\frac{1}{2}$ ---> the dilation is a reduction, because the scale factor is less than 1 and greater than zero

substitute

$\frac{1}{2}=\frac{A'C'}{AC}$

$AC=2A'C'$

therefore

The length of segment AC is two times the length of segment A'C'

5 0

2 years ago

Read 2 more answers

U divided by 25 =13 please do step by step and show work thanks :))

Anna71 [15]

Answer U/25=13
U=13 divided 1/25
U=13 multiply 25
U=325

6 0

3 years ago

Help ASAP its due today!

Genrish500 [490]

Answer:

The answer is D) 60

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

I need number 1 please and thank you

belka [17]

Answer:

It is the third one because of formula I² + 2I*II + II²

In your case I = 4x and II = 3

4 0

2 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

2 years ago