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Hatshy [7]
3 years ago
12

. [15 points] Alex is at the northernmost point of a circular parking lot with radius 26 feet. Dylan stands 22.4 feet west and 2

7 feet south of the southernmost point of the parking lot. Dylan walks due north until he hits the edge of the parking lot. Then, he turns and walks in a straight line towards the easternmost point of the parking lot. How close does Dylan get to Alex

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

31.925 ft

Step-by-step explanation:

A diagram is needed to visualize Dylan's movement to Alex see below

thus (-22.4)² + y²  = 26²

y² = 26² - (22.4)² = 174.24

y = -√174.2 = - 13.2 ft note due south

closest point at intersection

3/11*  ( x- 26) = -11/3 x * + 26

3/11 x - 78/11 = -11/3x + 26

3/11 x +11/3x = 26 + 78/11

130/33 x = 364/11

x = 364/11 * 33/130 = 8.4

then y = 3/11 * (x -26)

      x = 8.4 substitute, gives y = 3/11 * (8.4 -26) = -4.8

distance from (8.4 , -4.8) to (0 , 26)

√[(0 -8.4)² +  ( 26-(-4.8))² ] = √[( -8.4)² +  ( 30.8)² ] = 31.925 ft

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