With the f(x) = x^2 - 2x + 1 there is an even degree polynomial as the highest degree here is 2 and there is a positive leading coefficient as the coefficient for the highest degree is considered to be 1. Therefore all statements for f(x) is false.
With g(x) = x^3 +1 there is an odd degree polynomial as x is raised to 3 and there is a positive leading coefficient as x^3 is multiplied to 1. Therefore only the fourth statement holds to be true
Expression equivalent to
is ![(\sqrt[d]{3b})^2](https://tex.z-dn.net/?f=%28%5Csqrt%5Bd%5D%7B3b%7D%29%5E2)
Option D is correct.
Step-by-step explanation:
We need to find equivalent expression of: 
Solving:
We know that ![\frac{1}{d}= \sqrt[d]{}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd%7D%3D%20%5Csqrt%5Bd%5D%7B%7D)
So, the expression will become:

![=(\sqrt[d]{3b})^2](https://tex.z-dn.net/?f=%3D%28%5Csqrt%5Bd%5D%7B3b%7D%29%5E2)
So, expression equivalent to
is ![(\sqrt[d]{3b})^2](https://tex.z-dn.net/?f=%28%5Csqrt%5Bd%5D%7B3b%7D%29%5E2)
Option D is correct.
Keywords: Exponents
Learn more about Exponents at:
#learnwithBrainly
Answer:

Step-by-step explanation:
We assume the following problem: "Consider the following ways students might create their lists using the notation:
B for block, W for watch, R for ring, and A for airplane. The first letter represents the toy found in the first box, and the second letter represents the toy found in the second box. The first column represents getting the block in the first box, followed by each one of the other toys. The second column represents getting the watch in the first box, followed by each one of the other toys. The third column is developed with the ring in the first box, and the fourth column is developed with the airplane in the first box"
And the possible outcomes are:
BB WB RB AB
BW WW RW AW
BR WR RR AR
BA WA RA AA
As we can see we have 16 possibilities.
For this case if we use the independence of events we have the following rule. If A and B are independent events then:

Let A = Select an airplane from the total of 4 for the first box
B= Select an airplane from the total of 4 for the second box
For this case probability of getting an airplane selected in the first box is 1 out of 4 since we have just one outcome possible and 4 possible.

And the probability of getting an airplane selected in the second box is also 1/4 since for the first box selected we have the same number of optiosn for the second box , 4.

So then we have this:

A)
a+b=180 and a=2(b-30) using this in the first equation gives you:
2(b-30)+b=180
2b-60+b=180
3b-60=180
3b=240
b=80 so a=100
Andre's score was 100 and Brandon's score was 80.
b)
100x-200>50x-75 subtract 50x from both sides
50x-200>-75 add 200 to both sides
50x>125 divide both sides by 50
x>2.5