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Kay [80]
3 years ago
7

Find a quadratic function that models the data. round numerical values to the nearest whole number. f(x) = x2 x use the function

to predict the number of births for month 8. there will be about births.
Mathematics
1 answer:
vazorg [7]3 years ago
7 0

A quadratic function is a function that has a degree of 2. This shows that there will be about 72 births for month 8

<h3>Quadratic functions</h3>

A quadratic function is a function that has a degree of 2. Given the quadratic function shown:

f(x) = x² + x

where

x is the total months

In order to use the function to predict the number of births for month 8, we will substitute x = 8 into the function as shown:

f(x) = x² + x

f(8) = 8² + 8
f(8) = 72 births

This shows that there will be about 72 births for month 8

Learn more on quadratic function here: brainly.com/question/24380382

#SPJ4

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The graph below shows two polynomial functions, f(x) and g(x):
UNO [17]
With the f(x) = x^2 - 2x + 1 there is an even degree polynomial as the highest degree here is 2 and there is a positive leading coefficient as the coefficient for the highest degree is considered to be 1. Therefore all statements for f(x) is false.

With g(x) = x^3 +1 there is an odd degree polynomial as x is raised to 3 and there is a positive leading coefficient as x^3 is multiplied to 1.  Therefore only the fourth statement holds to be true
6 0
3 years ago
Read 2 more answers
Show your work on the question
Law Incorporation [45]

Expression equivalent to (3b)^{\frac{2}{d}} is (\sqrt[d]{3b})^2

Option D is correct.

Step-by-step explanation:

We need to find equivalent expression of: (3b)^{\frac{2}{d}}

Solving:

We know that \frac{1}{d}= \sqrt[d]{}

So, the expression will become:

(3b)^{\frac{2}{d}}

=(\sqrt[d]{3b})^2

So, expression equivalent to (3b)^{\frac{2}{d}} is (\sqrt[d]{3b})^2

Option D is correct.

Keywords: Exponents

Learn more about Exponents at:

  • brainly.com/question/13174254
  • brainly.com/question/13174255
  • brainly.com/question/5639299

#learnwithBrainly

8 0
3 years ago
Which of the following expressions does not equal: the sixth root of 81x^4y^8
DerKrebs [107]
\sqrt[6]{81x^4y^8}=\left[3^4x^4(y^2)^4\right]^\frac{1}{6}=\left[\left(3xy^2\right)^4\right]^\frac{1}{6}\\\\=\left(3xy^2\right)^{4\cdot\frac{1}{6}}=\left(3xy^2\right)^\frac{2}{3}\to A\\\\=\left(3xy^2\right)^\frac{2}{3}=\sqrt[3]{\left(3xy^2\right)^2}=\sqrt[3]{9x^2y^4}\to D\\\\=\left(3xy^2\right)^\frac{2}{3}=\left(3x\right)^\frac{2}{3}y^{2\cdot\frac{2}{3}}=\left(3x\right)^\frac{2}{3}y^\frac{4}{3}\to B\\\\\\Answer:C
4 0
4 years ago
8. Based on the multiplication rule for independent events, what is the probability of getting an airplane in both boxes? Explai
Furkat [3]

Answer:

P(A and B ) = \frac{1}{4}* \frac{1}{4}=\frac{1}{16}

Step-by-step explanation:

We assume the following problem: "Consider the following ways students might create their lists using the notation:

B for block, W for watch, R for ring, and A for airplane.  The first letter represents the toy found in the first box, and the second letter represents the toy found in the second  box. The first column represents getting the block in the first box, followed by each one of the other toys. The  second column represents getting the watch in the first box, followed by each one of the other toys. The third  column is developed with the ring in the first box, and the fourth column is developed with the airplane in the first  box"

And the possible outcomes are:

BB WB RB AB

BW WW RW AW

BR WR RR AR

BA WA RA AA

As we can see we have 16 possibilities.

For this case if we use the independence of events we have the following rule. If A and B are independent events then:

P(A and B) = P(A) *P(B)

Let A = Select an airplane  from the total of 4 for the first box

B= Select an airplane from the total of 4 for the second box

For this case probability of getting an airplane selected in the  first box is 1 out of 4 since we have just one outcome possible and 4 possible.

P(A) = \frac{1}{4}

And the probability of getting an airplane selected in the second box is also 1/4 since for the first box selected we have the same number of optiosn for the second box , 4.

P(B) = \frac{1}{4}

So then we have this:

P(A and B ) = \frac{1}{4} \frac{1}{4}=\frac{1}{16}

5 0
4 years ago
A. The sum of Andre and Brandon scores on a math quiz is 180. Andres score is 2 times more than 30 less than Brandon score. Find
pantera1 [17]
A)

a+b=180 and a=2(b-30) using this in the first equation gives you:

2(b-30)+b=180

2b-60+b=180

3b-60=180

3b=240

b=80 so a=100

Andre's score was 100 and Brandon's score was 80.

b)

100x-200>50x-75  subtract 50x from both sides

50x-200>-75  add 200 to both sides

50x>125  divide both sides by 50

x>2.5
8 0
3 years ago
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