(2x² - 8x - 10) ÷ 2 = 0
x² - 4x - 5 = 0
x² + x - 5x - 5 = 0
x(x+1) - 5(x+1) = 0
(x+1)(x-5) = 0
x+1 = 0 or x-5 = 0
x = -1 or x= 5
S = {-1;5}
Hey there!
One way to do this is find all the factors of 6 and then see which pair fit the requirements.
The factors of 6 are 1, 2, 3, and 6. (Note: There can be negative factors, but I am going to leave them out since it is asking for positive integers.)
You can find them by asking if each number can go into 6.
1, 2, 3, and 6 all go into 6, while 4 and 5 do not.
The requirements we have is that they must be consecutive <u>and</u> have a product of 6.
Consecutive means right after one another.
The only numbers that fit this are 2 and 3.
2 x 3 = 6
Hope this helps!
Any of the tens i think (10=60, 20+50, etc.), but i am not too sure what is implied by regrouping. if i am right in thinking this only means "carrying" a digit after adding, then anything that adds up to 70 would work unless the sum of the digits in the ones place exceeded 9.
Answer:
The answer is 40 and I calculated it, it’s true
Step-by-step explanation:
I promise