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lesantik [10]
3 years ago
8

Given the following exponential function, identify whether the change represents

Mathematics
1 answer:
Pavel [41]3 years ago
7 0

Answer:

3%

Step-by-step explanation:

This equation represents exponential decay. Whenever the base is less than 1, the function represents decay. When the base is greater than 1, the function represents growth. In this case, the base is .97 which is less than 1, representing decay.

The formula for exponential decay is y=a(1-r)x.

r is the decay rate, expressed as a decimal.

In this case, r = .03 which represents 3%!

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Marat540 [252]

Answer:

Area = 530 cm^2

Step-by-step explanation:

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2 years ago
Last month in the village of 125 people we’re issued a parking ticket. This month only 83 people were issued one. What was the p
natita [175]

Answer:

the percent reduction is <u>33.6%</u> and the number of people who were issued a parking ticket are <u>42</u>.

Step-by-step explanation:

Given:

Last month in the village of 125 people were issued a parking ticket.

This month only 83 people were issued one.

Now, to find the percent reduction from this month to last month and the number of people who were issued a Parking ticket.

So, the reduction of the number of people who were issued a Parking ticket from this month to last month are:

125 people - 83 people = 42 people.

Thus, 42 people reduction from this month to last month.

Now, to get the percent reduction:

\frac{42}{125}\times 100.

=\frac{4200}{125}

=\ 33.6\%

Therefore, the percent reduction is 33.6% and the number of people who were issued a parking ticket are 42.

7 0
3 years ago
In Val's class, the ratio of students who ate enchiladas for lunch to the students who ate tacos was 14:20. Which of the followi
fgiga [73]
An equivalent ratio would be 7:10 or 70:100 or 42:60 and so on...
6 0
3 years ago
Simplify 0, -6 please :(
snow_tiger [21]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc pls help me
VladimirAG [237]

a+b+c=0

[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]

[a^2+b^2+c^2+2ab+2ac+2bc=0]

[a^2+b^2+c^2=-(2ab+2ac+2bc)]

[a^2+b^2+c^2=-2(ab+ac+bc)] (i)

also

[a=-b-c]

[a^2=-ab-ac] (ii)

[-c=a+b]

[-bc=ab+b^2] (iii)

adding (ii) and (iii) ,we have

[a^2-bc=b^2-ac] (iv)

devide (i) by (iv)

[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
8 0
3 years ago
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