Answer:
Step-by-step explanation:
1st . 1.3^2= 1.69
1.4^2= 1.96
It's not bettween 1.3 & 1.4
2. 1.4^2=1.96
1.5^2= 2.25
it's betteen 1.4 & 1.5
3 . 1.4 & 1.5 so it's eqaul 1.4
While you cannot solve 946x+642y=911 for numerical values of x and y, you can indeed solve 946x+642y=911 first for x and then for y:
-911 - 642y
For x: 946x+642y=911 becomes 946x = 911 - 642y, or x = ------------------
946
911-946x
For y: 946x+642y=911 becomes 642y = 911-946x, or y = ---------------
642
0 < /6/ (absolute value)
That is your inequality since the subject is about the distance away from zero then using common sense you would make the 6 get put in between the 2 absolute value lines ( not trying to be rude, if the explanation seems rude to you im sorry)
Any value? you could use 0 or 1 or 2. All three of these are a group of many that would wokr. Any would work!
Answer:
-5 and -10
Step-by-step explanation:
